我有一個活動,其利用一個FragmentTabHost
的,因此,每個標籤都有它裏面的片段。在第一個標籤中,我有兩個嵌套片段,一個在屏幕的上半部分,另一個在下半部分。底部的片段使用ViewPager
掃描幾個LinearLayouts
。這一切都很好。FragmentTabHost,嵌套片段和ViewPager
直到您移到另一個選項卡並返回第一個。底部的嵌套片段不再出現,但頂部的嵌套片段不會。
下面是一些代碼展示了我的用法:
這是我如何用我的主要活動:
public class MainActivity extends SherlockFragmentActivity
{
private FragmentTabHost mTabHost;
@Override
protected void onCreate(Bundle savedInstanceState)
{
super.onCreate(savedInstanceState);
setContentView(R.layout.main_activity_layout_vert);
mTabHost = (FragmentTabHost)findViewById(android.R.id.tabhost);
mTabHost.setup(this, getSupportFragmentManager(), R.id.realtabcontent);
mTabHost.addTab(mTabHost.newTabSpec("TAB1").setIndicator("", getResources().getDrawable(R.drawable.tab1_selector)), Tab1Fragment.class, null);
mTabHost.addTab(mTabHost.newTabSpec("TAB2").setIndicator("", getResources().getDrawable(R.drawable.tab2_selector)), Tab2Fragment.class, null);
}
}
這裏是我如何使用片段爲TAB1:
public class Tab1Fragment extends SherlockFragment
{
private NestedFragment1 mNestedFrag1 = null;
private NestedFragment2 mNestedFrag2 = null;
@Override
public void onCreate(Bundle inSavedInstanceState)
{
super.onCreate(inSavedInstanceState);
mNestedFrag1 = new NestedFragment1();
mNestedFrag2 = new NestedFragment2();
FragmentManager fragManager = getChildFragmentManager();
FragmentTransaction fragTransaction = fragManager.beginTransaction();
fragTransaction.add(R.id.nested_frag1_container, mNestedFrag1, "Frag1");
fragTransaction.add(R.id.nested_frag2_container, mNestedFrag2, "Frag2");
fragTransaction.commit();
}
@Override
public void onDestroy()
{
FragmentManager fragManager = getChildFragmentManager();
FragmentTransaction fragTransaction = fragManager.beginTransaction();
fragTransaction.remove(mNestedFrag1);
fragTransaction.remove(mNestedFrag2);
fragTransaction.commit();
}
}
這裏是我如何使用第二嵌套片段(即消失的一個):
public class NestedFragment2 extends SherlockFragment
{
private MyPageAdapter mPageAdapter;
private ViewPager mViewPager;
@Override
public void onCreate(Bundle inSavedInstanceState)
{
super.onCreate(inSavedInstanceState);
mPageAdapter = new MyPageAdapter();
}
@Override
public void onDestroy()
{
super.onDestroy();
}
@Override
public View onCreateView(LayoutInflater inflater, ViewGroup container, Bundle savedInstanceState)
{
View toReturn = inflater.inflate(R.layout.nested_fragment1_layout_top, container, false);
mViewPager = (ViewPager)toReturn.findViewById(R.id.viewpager);
mViewPager.setAdapter(mPageAdapter);
mViewPager.setOffscreenPageLimit(5);
return toReturn;
}
private class MyPageAdapter extends PagerAdapter
{
@Override
public Object instantiateItem(ViewGroup container, int position)
{
View page = getActivity().getLayoutInflater().inflate(R.layout.view_pager_controls_layout, container, false);
container.addView(page);
return page;
}
@Override
public void destroyItem(ViewGroup container, int position, Object object)
{
container.removeView((View)object);
}
@Override
public int getCount()
{
return 5;
}
@Override
public float getPageWidth(int position)
{
return 1;
}
@Override
public boolean isViewFromObject(View view, Object object)
{
return(view == object);
}
}
}
想法?
我已經將它設置爲5 難道你誤會? viewpager與標籤無關。它用在第一個選項卡內的嵌套片段中。 – KairisCharm
我需要看看你是如何實現2嵌套片段。 – Dororo
請查看我的編輯到我的文章。 – KairisCharm