任何其他替代寫這個SQL查詢

選擇數據庫查找表的最後日期（StorageDate列）爲每個記錄
看看是否有更多的則是一個在爲相同的ID第一步（ID列）
然後查看找到的條目的日期（StorageDate column）如果DuplicateID是= 2

因此，如果表具有如下的數據：

ID |StorageDate | DuplicateTypeID 
1 |2014-10-22 | 1 
1 |2014-10-22 | 2 
1 |2014-10-18 | 1 
2 |2014-10-12 | 1 
3 |2014-10-11 | 1 
4 |2014-09-02 | 1 
4 |2014-09-02 | 2

然後，我應該得到以下結果

ID 
1 
4

我已經寫了下面的查詢，但它實在是太慢了，我想知道是否有人有更好的方式來寫。

SELECT DISTINCT(TD.RecordID) 
FROM dbo.MyTable TD 
JOIN (
    SELECT T1.RecordID, T2.MaxDate,COUNT(*) AS RecordCount 
    FROM MyTable T1 WITH (nolock) 
    JOIN (
    SELECT RecordID, MAX(StorageDate) AS MaxDate 
      FROM MyTable WITH (nolock) 
      GROUP BY RecordID)T2 
    ON T1.RecordID = T2.RecordID AND T1.StorageDate = T2.MaxDate 
    GROUP BY T1.RecordID, T2.MaxDate 
    HAVING COUNT(*) > 1 
    )PT ON TD.RecordID = PT.RecordID AND TD.StorageDate = PT.MaxDate 
    WHERE TD.DuplicateTypeID = 2

來源

2014-12-03 bp_dbdeveloper

會不會有一種情況，一個ID爲duplicatetype 2，但*犯規*顯示在列表中的？ – paqogomez 2014-12-03 21:57:55

您可以使用分析功能rank，你可以試試這個查詢嗎？

Select recordId from 
(
    select *, rank() over (partition by recordId order by [StorageDate] desc) as rn 
    from mytable 
) T 
where rn =1 
group by recordId 
having count(*) >1 
and sum(case when duplicatetypeid =2 then 1 else 0 end) >=1

來源

2014-12-03 22:04:45 radar

試試這個，看看性能如何去：

;WITH 
    tmp AS 
    (
     SELECT  *, 
        RANK() OVER (PARTITION BY ID ORDER BY StorageDate DESC) AS StorageDateRank, 
        COUNT(ID) OVER (PARTITION BY ID, StorageDate) AS StorageDateCount 
     FROM  MyTable 
    ) 

SELECT DISTINCT ID 
FROM tmp 
WHERE StorageDateRank = 1 -- latest date for each ID 
    AND StorageDateCount > 1 -- more than 1 entry for date 
    AND DuplicateTypeID = 2 -- DuplicateTypeID = 2

來源

2014-12-03 22:06:37

任何其他替代寫這個SQL查詢

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