這是一個正確使用'分區'的問題嗎？

Question

我想爲此使用分析，因爲我有其他幾個相似的統計數據，我想要 報告。

問：使用Oracle Analytics，我怎樣才能在每個機場只有一行？

with detail_records as 
(select 1 as passenger_id, 'ATL' as airport, 'E4' as gate, 10 as luggage_weight from dual union all 
select 2 as passenger_id, 'ATL' as airport, 'E4' as gate, 25 as luggage_weight from dual union all 
select 2 as passenger_id, 'SFO' as airport, 'E4' as gate, 20 as luggage_weight from dual union all 
select 3 as passenger_id, 'SFO' as airport, 'E4' as gate, 30 as luggage_weight from dual union all 
select 4 as passenger_id, 'SFO' as airport, 'E4' as gate, 40 as luggage_weight from dual 
) 
select airport, 
     count(*) over (partition by airport) as airport_count, 
     sum(luggage_weight) over (partition by airport, gate) as a_g_weight 
from detail_records 
where gate='E4' 

結果

AIRPORT AIRPORT_COUNT A_G_WEIGHT 
ATL  2    35 
ATL  2    35 
SFO  3    90 
SFO  3    90 
SFO  3    90 

預期的效果

Airport Airport_count A_G_WEIGHT 
ATL  2    35 
SFO  3    90 

Answer 1

正如Wernfried說，你找DISTINCT關鍵字。

既然 「乘客ID」 列沒有關係，並希望避免重複，你必須把它這樣：

with detail_records as 
(select 1 as passenger_id, 'ATL' as airport, 'E4' as gate, 10 as luggage_weight from dual union all 
select 2 as passenger_id, 'ATL' as airport, 'E4' as gate, 25 as luggage_weight from dual union all 
select 2 as passenger_id, 'SFO' as airport, 'E4' as gate, 20 as luggage_weight from dual union all 
select 3 as passenger_id, 'SFO' as airport, 'E4' as gate, 30 as luggage_weight from dual union all 
select 4 as passenger_id, 'SFO' as airport, 'E4' as gate, 40 as luggage_weight from dual 
) 
select distinct airport, 
     count(*) over (partition by airport) as airport_count, 
     sum(luggage_weight) over (partition by airport, gate) as a_g_weight 
from detail_records 
where gate='E4' 

Answer 2

使用簡單GROUP BY查詢

select airport, 
     count(*) as airport_count, 
     sum(luggage_weight) as a_g_weight 
from detail_records 
where gate='E4' 
group by airport