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這是我的某個程序的代碼。但是,什麼是殺害我的是,在功能getTotalX
,在內部如果塊的for循環,當標誌break語句後更新爲0,事實上,它得到更新回到1。這是爲什麼發生?我認爲break語句可以幫助我擺脫for循環,並直接轉到下一個語句。break語句後分配的值會發生什麼?
#include <stdio.h>
int getTotalX(int a_size, int* a, int b_size, int* b){
int min = a[a_size-1];
int max = b[0];
int count = 0;
for(int i = min; i <= max; i++){
int flag1 = 1, flag2 = 1;
for(int j = 0; j < a_size; j++){
printf("In array a,value of %d mod %d is %d \n",i,a[j],i%a[j]);
if((i % a[j]) != 0){
int flag1 = 0;
printf("flag1 set to 0. Check flag1 = %d\n",flag1);
break;
}
}
printf("Checkpoint2, value of flag1 = %d\n",flag1);
if(flag1 != 0){
for(int k =0; k < b_size; k++){
printf("In array b,value of %d mod %d is %d \n",b[k],i,b[k]%i);
if((b[k] % i) != 0){
int flag2 = 0;
printf("flag2 set to 0. Check flag2 = %d\n",flag2);
break;
}
}
}
printf("Checkpoint3, value of flag2 = %d\n",flag2);
if((flag1 == 1) && (flag2 == 1)){
printf("Value of flag1 = %d and flag2 = %d\n",flag1,flag2);
printf("%d \n ",i);
count++;
}
}
return(count);
}
int main() {
int n;
int m;
scanf("%d %d", &n, &m);
int *a = malloc(sizeof(int) * n);
for(int a_i = 0; a_i < n; a_i++){
scanf("%d",&a[a_i]);
}
int *b = malloc(sizeof(int) * m);
for(int b_i = 0; b_i < m; b_i++){
scanf("%d",&b[b_i]);
}
int total = getTotalX(n, a, m, b);
printf("%d\n", total);
return 0;
}
所有的打印聲明都是爲了幫助我弄清楚我哪裏出錯了。我可以改變邏輯來使其工作,但請幫助我理解爲什麼會發生這種情況?
的好處['-Wshadow'](https://stackoverflow.com/questions/25151524/get-warning-when-a-variable-is-shadowed)不能被低估。 – dhke
哦,太棒了!哇。 – momo