從2個插入查詢中獲得第二個表的編號

Question

我有兩個表（用戶和訂閱）正在插入數據，但是表訂閱從表格用戶使用$sid = mysqli_insert_id($db)獲取用戶標識現在我想從表2中獲取sid，這樣我可以將它傳遞給支付網關。這裏是我的代碼段

if (isset($_POST['online'])) { 
$_SESSION['lname'] = $db->real_escape_string($_POST['lname']); 
$_SESSION['fname'] = $db->real_escape_string($_POST['fname']); 
$_SESSION['email'] = $db->real_escape_string($_POST['email']); 
$_SESSION['tele'] = $db->real_escape_string($_POST['tele']); 
$_SESSION['sex'] = $db->real_escape_string($_POST['sex']); 
$_SESSION['address'] = $db->real_escape_string($_POST['address']); 
$_SESSION['occupation'] = $db->real_escape_string($_POST['occupation']); 
$_SESSION['org'] = $db->real_escape_string($_POST['org']); 
$_SESSION['amount'] = $db->real_escape_string($_POST['amount']); 



$sql = $db->query("INSERT INTO user (fname, lname, email, tele, sex, occupation, org) 
          VALUES('".$_SESSION['fname']."', '".$_SESSION['lname']."', 
          '".$_SESSION['email']."', 
         '".$_SESSION['tele']."', '".$_SESSION['sex']."', '".$_SESSION['occupation']."', 
         '".$_SESSION['org']."')"); 
$sid = mysqli_insert_id($db); 

$sql = $db->query("INSERT INTO subscription (userid, amount, event, status, statusmessage) 
          VALUES('$sid', '".$_SESSION['amount']."','Main Summit', '0', 'Pending Payment by user')"); 

Answer 1

只需再打電話mysqli_insert_id：

$sql = $db->query("INSERT INTO user (fname, lname, email, tele, sex, occupation, org) 
          VALUES('".$_SESSION['fname']."', '".$_SESSION['lname']."', 
          '".$_SESSION['email']."', 
         '".$_SESSION['tele']."', '".$_SESSION['sex']."', '".$_SESSION['occupation']."', 
         '".$_SESSION['org']."')"); 
$userid = mysqli_insert_id($db); 

$sql = $db->query("INSERT INTO subscription (userid, amount, event, status, statusmessage) 
          VALUES('$userid', '".$_SESSION['amount']."','Main Summit', '0', 'Pending Payment by user')"); 

$subscriptionid = mysqli_insert_id($db); 

我不知道你的$ DB類，但你應該use prepared statements而不是串聯參數。