查找在每個位置ID花費的時間

我想知道每個ID在起始位置花了多少時間。查找在每個位置ID花費的時間

例如，在下面的數據集中，啓動id爲286的Geohash爲「abcdef」。 Geohash「abcdef」出現在3個地方爲Id 286. 因此Id 286花費的總時間是（2017-02-13 12：33：02.063 UTC - 2017-02-13 12:24:36 UTC）和（2017-02-13 12:34:29 UTC - 2017-02-13 12:33:08 UTC）。

 Id   DateTime      Latitude  Longitude Geohash 
     0 286  2017-02-13 12:24:36 UTC  40.769230 -73.01205  abcdef 
     1 286  2017-02-13 12:33:02.063 UTC 40.769230 -73.01202  abcdef 
     2 286  2017-02-13 12:33:05.063 UTC 40.769230 -73.01202  cvzvvv 
     3 286  2017-02-13 12:33:08 UTC  40.769280 -73.01212  abcdef 
     4 286  2017-02-13 12:34:29 UTC  40.769306 -73.01207  hsffds 
     5 368  2017-02-13 00:23:07.063 UTC 33.392820 -111.8262  weruio 
     6 141  2017-02-13 00:00:41 UTC  33.287117 -111.84150 oqruqq

不確定pandas數據框中是否有任何函數可以實現此操作。

任何幫助將非常感激。！

來源

2017-03-16 user3447653

下面是BigQuery的標準SQL

#standardSQL 
SELECT 
    Id, Geohash, MIN(DateTime) AS StartDateTime, SUM(TimeSpent) AS TimeSpent 
FROM (
    SELECT 
    Id, Geohash, DateTime, 
    TIMESTAMP_DIFF(LEAD(DateTime) OVER(PARTITION BY Id ORDER BY DateTime), DateTime, SECOND) AS TimeSpent, 
    FIRST_VALUE(Geohash) OVER(PARTITION BY Id ORDER BY DateTime) AS FirstGeohash 
    FROM yourTable 
) 
WHERE Geohash = FirstGeohash 
GROUP BY Id, Geohash

你可以從你的榜樣虛擬數據測試：

#standardSQL 
WITH yourTable AS (
    SELECT 286 AS Id, TIMESTAMP '2017-02-13 12:24:36 UTC' AS DateTime, 40.769230 AS Latitude, -73.01205 AS Longitude, 'abcdef' AS Geohash UNION ALL 
    SELECT 286, TIMESTAMP '2017-02-13 12:33:02.063 UTC', 40.769230, -73.01202, 'abcdef' UNION ALL 
    SELECT 286, TIMESTAMP '2017-02-13 12:33:05.063 UTC', 40.769230, -73.01202, 'cvzvvv' UNION ALL 
    SELECT 286, TIMESTAMP '2017-02-13 12:33:08 UTC', 40.769280, -73.01212, 'abcdef' UNION ALL 
    SELECT 286, TIMESTAMP '2017-02-13 12:34:29 UTC', 40.769306, -73.01207, 'hsffds' UNION ALL 
    SELECT 368, TIMESTAMP '2017-02-13 00:23:07.063 UTC', 33.392820, -111.8262, 'weruio' UNION ALL 
    SELECT 141, TIMESTAMP '2017-02-13 00:00:41 UTC', 33.287117, -111.84150, 'oqruqq' 
) 
SELECT 
    Id, Geohash, MIN(DateTime) AS StartDateTime, SUM(TimeSpent) AS TimeSpent 
FROM (
    SELECT 
    Id, Geohash, DateTime, 
    TIMESTAMP_DIFF(LEAD(DateTime) OVER(PARTITION BY Id ORDER BY DateTime), DateTime, SECOND) AS TimeSpent, 
    FIRST_VALUE(Geohash) OVER(PARTITION BY Id ORDER BY DateTime) AS FirstGeohash 
    FROM yourTable 
) 
WHERE Geohash = FirstGeohash 
GROUP BY Id, Geohash

結果如下

Id Geohash  StartDateTime   TimeSpent  
286 abcdef  2017-02-13 12:24:36 UTC  590  
368 weruio  2017-02-13 00:23:07 UTC  null  
141 oqruqq  2017-02-13 00:00:41 UTC  null

請注意：上述590是timespent的三個頁面的總和（以秒爲單位） - 不只是兩頁，因爲它是你的問題說 - 我認爲這只是錯字就在你身邊

來源

2017-03-16 05:47:04

如果我理解正確的話，你想是這樣的：

def timedelta(df): 
    df = df.sort_values(by='DateTime') 
    return df.iloc[0]['DateTime'] - df.iloc[-1]['DateTime'] 

df.groupby(['Id', 'Geohash']).apply(timedelta)

來源

2017-03-16 04:25:49

查找在每個位置ID花費的時間

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