-3
我有這個下面的查詢對於XML在SQL Server - 添加子元素
返回此XML文件格式
我怎樣才能得到它的這種格式?
請幫幫忙, 源代碼
SELECT top 1
(SELECT top 1
count(*)AS 'number-of-accounts',
sum(br.cnsmr_accnt_bckt_crrnt_bal_amnt) AS 'total-value-of-account-payment',
'' AS 'date-of-turnover',
'' AS 'is-conversion-job'
FROM
cnsmr as c
inner join cnsmr_accnt as ca ON c.cnsmr_id = ca.cnsmr_id
inner join cnsmr_accnt_bckt_bal_rprtng as br on ca.cnsmr_accnt_id = br.cnsmr_accnt_id
FOR XML PATH('payment-import-header'), TYPE),
(SELECT top 1
br.cnsmr_accnt_bckt_crrnt_bal_amnt AS 'payment-amount',
'' AS 'bucket-transaction-type',
'' AS 'tendered-date',
'' AS 'entered-date',
'' AS 'payment-location-code',
'' AS 'payment-memo-code',
'' AS 'payment-comments',
'' AS 'external-reference-identifier'
FROM
cnsmr as c
inner join cnsmr_accnt as ca ON c.cnsmr_id = ca.cnsmr_id
inner join cnsmr_accnt_bckt_bal_rprtng as br on ca.cnsmr_accnt_id = br.cnsmr_accnt_id
FOR XML PATH('consumer-payment'), ROOT('consumer-payment-import'),TYPE)
FOR XML RAW (''), ROOT ('consumer-payment-import-job'), ELEMENTS XSINIL;
複製/粘貼代碼*到你的問題*。 *不*上傳代碼圖片。我們無法用圖片做任何事情。 – Siyual