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我有一個data.frame data
如下。基於另一個因素的重排因子水平
data <- structure(list(fac1 = structure(c(6L, 16L, 4L, 14L, 1L, 7L, 3L,
2L, 15L, 10L, 11L, 9L, 8L, 5L, 13L, 12L), .Label = c("dd85",
"ee01", "ee12", "ee78", "gs85", "jj45", "jj63", "qe89", "qq74",
"tt23", "tt78", "vd41", "vd51", "ww77", "yy25", "yy85"), class = "factor"),
fac2 = structure(c(1L, 1L, 1L, 1L, 2L, 2L, 2L, 2L, 3L, 3L,
3L, 3L, 4L, 4L, 4L, 4L), .Label = c("md", "av", "zr", "kj"), class = "factor")), .Names = c("fac1",
"fac2"), row.names = c(NA, 16L), class = "data.frame")
levels(data$fac1)
levels(data$fac2)
data
fac1 fac2
1 jj45 md
2 yy85 md
3 ee78 md
4 ww77 md
5 dd85 av
6 jj63 av
7 ee12 av
8 ee01 av
9 yy25 zr
10 tt23 zr
11 tt78 zr
12 qq74 zr
13 qe89 kj
14 gs85 kj
15 vd51 kj
16 vd41 kj
levels(data$fac1)
[1] "dd85" "ee01" "ee12" "ee78" "gs85" "jj45" "jj63" "qe89" "qq74" "tt23" "tt78" "vd41" "vd51" "ww77" "yy25" "yy85"
levels(data$fac2)
[1] "md" "av" "zr" "kj"
如何的fac2
的基礎上重新排列的fac1
水平?
我試過factor(data, levels=data[order(data$fac2),], ordered=TRUE)
根據這question,但它提供了兩個級別。
factor(data, levels=data[order(data$fac2),], ordered=TRUE)
fac1 fac2
c(6, 16, 4, 14, 1, 7, 3, 2, 15, 10, 11, 9, 8, 5, 13, 12) c(1, 1, 1, 1, 2, 2, 2, 2, 3, 3, 3, 3, 4, 4, 4, 4)
2 Levels: c(6, 16, 4, 14, 1, 7, 3, 2, 15, 10, 11, 9, 8, 5, 13, 12) < ...