嗨我想用繼承的糖ORM 。繼承與糖ORM
我的課表:
public class Building extends SugarRecord<Building> {
protected String name;
}
和:
public class Kitchen extends Building{
int value =1;
}
當我保存一些廚房,一一列舉了,我只能查詢作爲廚房的廚房,但不能建築物。
我能不能解決這個問題或者Sugar ORM沒有這個功能?
記錄:
List<Building> buildingsList = Building.listAll(Building.class);
for (Building buidling : buildingsList) {
Log.i("Buildings: ", buidling.toString());
}
List<Kitchen> kitchenList = Kitchen.listAll(Kitchen.class);
for (Kitchen kitchen : kitchenList) {
Log.i("Kitchens: ", kitchen.toString());
}
輸出:
//Adding Kitchens,
10-04 13:10:53.212: I/Sugar(12104): Kitchen saved : 1
10-04 13:10:58.058: I/Sugar(12104): Kitchen saved : 2
10-04 13:10:58.455: I/Sugar(12104): Kitchen saved : 3
//Listing Buildings, nothing
10-04 13:11:16.993: D/SQL Log(12104): SQLiteQuery: SELECT * FROM BUILDING
*NONE*
//Listing as Kitchens, here they are:
10-04 13:11:16.993: D/SQL Log(12104): SQLiteQuery: SELECT * FROM KITCHEN
10-04 13:11:16.994: I/Kitchens:(12104): [email protected]
10-04 13:11:16.994: I/Kitchens:(12104): [email protected]
10-04 13:11:16.994: I/Kitchens:(12104): [email protected]
如果您打算考慮另一個可以輕鬆處理繼承的ORM,請嘗試[JDXA](http://softwaretree.com/v1/products/jdxa/jdxa.html)。 JDXA可以在類層次結構中多態獲取對象。此外,JDXA不要求您從任何基類擴展模型類。 –