隨機帖子部件腳本不工作在博主

我想做一個隨機發布的小部件工作在我的博客（博客），但瀏覽器不斷給我一個錯誤，說該腳本沒有響應：「腳本上此頁面可能正忙，或者它可能已停止響應，您現在可以停止腳本，在調試器中打開腳本，或者讓腳本繼續隨機帖子部件腳本不工作在博主

腳本：。http://testeshoon.blogspot.pt/:4792「

腳本來與模板。已經嘗試從網絡上的其他腳本，但他們都做同樣的事情。我試圖解決這個過去兩天，但無法弄清楚問題是什麼。

任何人都可以幫助我嗎？真的需要這個工作，至少，在2個部件。

爲最近的帖子嘗試腳本，那些工作很好，但隨機的腳本沒有。

<ul id='random-posts'> 
 
\t <script type='text/javaScript'> 
 
\t \t var rdp_numposts = 2; 
 
\t \t var rdp_snippet_length = 100; 
 
\t \t var rdp_info = 'yes'; 
 
\t \t var rdp_comment = 'Comments'; 
 
\t \t var rdp_disable = 'Comments Disabled'; 
 
\t \t var rdp_current = []; 
 
\t \t var rdp_total_posts = 0; 
 
\t \t var rdp_current = new Array(rdp_numposts); 
 

 
\t \t function totalposts(json) { 
 
\t \t \t rdp_total_posts = json.feed.openSearch$totalResults.$t 
 
\t \t } 
 
\t \t document.write('<script type=\"text/javascript\" src=\"/feeds/posts/default/-/noticias?alt=json-in-script&max-results=0&callback=totalposts\"><\/script>'); 
 

 
\t \t function getvalue() { 
 
\t \t \t for (var i = 0; i < rdp_numposts; i++) { 
 
\t \t \t \t var found = false; 
 
\t \t \t \t var rndValue = get_random(); 
 
\t \t \t \t for (var j = 0; j < rdp_current.length; j++) { 
 
\t \t \t \t \t if (rdp_current[j] == rndValue) { 
 
\t \t \t \t \t \t found = true; 
 
\t \t \t \t \t \t break 
 
\t \t \t \t \t } 
 
\t \t \t \t }; 
 
\t \t \t \t if (found) { 
 
\t \t \t \t \t i-- 
 
\t \t \t \t } else { 
 
\t \t \t \t \t rdp_current[i] = rndValue 
 
\t \t \t \t } 
 
\t \t \t } 
 
\t \t }; 
 

 
\t \t function get_random() { 
 
\t \t \t var ranNum = 1 + Math.round(Math.random() * (rdp_total_posts - 1)); 
 
\t \t \t return ranNum 
 
\t \t }; 
 
\t </script> 
 
\t <script type='text/javaScript'> 
 
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\t </script> 
 
</ul>

來源

2016-01-21 CmR

在for循環的第一行添加console.log（i）報告會發生什麼。您可以在瀏覽器的控制檯窗口中看到它的輸出。 – Glubus

如果'rdp_total_posts'設置爲零，並且您在get_random函數中使用var varNum = 1 + Math.round（Math.random（）*（rdp_total_posts - 1）），那麼結果不會是零或更少那麼零？ – Dennis1679

@ Dennis1679，不，它是非共享第三方腳本的回調。 –

讓我們假設你想從n可能的數字k個不同的數字（隨機指標後）。這裏是一個實施

function getRandomSubset(n, k) { 
    if (k > n) { 
     //impossible 
     return; 
    } 
    //initializing the result set as empty 
    var output = []; 
    //creating a variable 
    var input; 
    //we need k distinct random numbers 
    while (k-- > 0) { 
     //we get a random integer, 0 <= input < n 
     input = Math.floor(Math.random() * n); 
     //if it is duplicated, increment it inside the n'th modulo class until a new value is found 
     while (output.indexOf(input) >= 0) { 
      input = (input + 1) % n; 
     } 
     //store the new distinct value into the results 
     output[output.length] = input; 
    } 
    return output; 
}

還有很多其他可能的方法。

來源

2016-01-21 14:48:59

隨機帖子部件腳本不工作在博主

回答

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