更改選擇連接通過事先從Oracle到SQL Server

Question

您好，我在Oracle數據庫中擁有這部分視圖，並且必須在Microsoft Sql Server上對其進行更改。

with V_LOCHIERARHY_N 
(nr, nivel, location, parent, systemid, siteid, orgid, count_a, count_wo, children) 
AS 
SELECT  LEVEL, LPAD (' ', 2 * (LEVEL - 1)) || l.LOCATION nivel, 
       LOCATION, PARENT, systemid, siteid, orgid, 
      (SELECT COUNT (a.ancestor) 
      FROM locancestor a 
      WHERE a.LOCATION = l.LOCATION AND a.siteid = l.siteid), 
        NVL (COUNT (w.wonum), 0) 
      FROM maximo.workorder w 

      WHERE ( w.reportdate > 
          TO_TIMESTAMP ('2006-06-19 00:00:01', 
             'YYYY-MM-DD HH24:MI:SS.FF' 
             ) 
        AND w.istask = 0 
        AND w.worktype <> 'P' 
        AND w.LOCATION = l.LOCATION 
       ) 
       AND w.status <> 'CAN'), 
      l.children 
    FROM lochierarchy l 
    START WITH l.LOCATION = 'StartPoint' 
    CONNECT BY PRIOR l.LOCATION = l.PARENT AND l.siteid = 'SiteTest' 

我需要從這個腳本中返回一個給定條目的所有子節點（可以在位置表中找到的子節點的描述）。

我有下一列的表：

Location Parent  Systemid Children Siteid Origid Lochierarchyid 
A001  StartPoint Primary 2  SiteTest X  106372 
A002  A001  Primary 2  SiteTest X  105472 
A003  A002  Primary 0  SiteTest X  98654 
A004  A002  Primary 1  SiteTest X  875543 
A004B A004  Primary 0  SiteTest X  443216 
B005  StartPoint Primary 0  SiteTest X  544321 

例如，對於給定的條目A001將返回

---

A002  
A003  
A004 
    A004B  
B005 

我做下面這個觀點，但我不知道如何將其與第一個整合。此外，它不會返回我的列表中corectly爲了

Parent 
Children 1 of parent 
    Children a of children 1 
    children b of children 1 
children 2 of parent 
    children a1 of children 2 and so on. 

---

WITH testCTE AS 
(
    SELECT l.parent, l.location as child, l.location, l.lochierarchyid 
    FROM lochierarchy l 
    where location='SecondLocation' --and siteid='SiteTest' 
     UNION ALL 
    SELECT c.Parent, l.parent, l.location, l.lochierarchyid 
    FROM lochierarchy l 
    INNER JOIN testCTE c ON l.parent = c.location 
) 
    SELECT * 
    FROM testCTE c 
    order BY c.parent,child asc 
; 

可以請人幫助我嗎？ :)

Answer 1

下面是如何使用遞歸查詢來做到這一點（在Oracle中，我知道的唯一的味道）。 「網絡」報道SQL Server也實現了遞歸查詢，並且使用相同的語法（我相信所有這些都符合SQL標準，所以這並不奇怪）。試一試。

我沒有創建表格，而是將所有測試數據放在第一個CTE中。當您嘗試此解決方案時，首先刪除名爲inputs的CTE，然後在查詢的其餘部分使用您的實際表名。

with 
    inputs (location, parent) as (
     select 'A001' , 'Downstream' from dual union all 
     select 'A002' , 'A001'  from dual union all 
     select 'A003' , 'A002'  from dual union all 
     select 'A004' , 'A002'  from dual union all 
     select 'A004B', 'A004'  from dual union all 
     select 'B005' , 'Downstream' from dual 
    ), 
    r (lvl, location) as (
     select 1, location 
     from inputs 
     where parent = 'Downstream' 
     union all 
     select r.lvl + 1, i.location 
     from r join inputs i on r.location = i.parent 
    ) 
    search depth first by lvl set ord 
select lpad(' ', 2 * (lvl-1), ' ') || location as location 
from r 
order by ord 
; 


LOCATION 
-------------------- 
A001 
    A002 
    A003 
    A004 
     A004B 
B005 

6 rows selected. 

ADDED：看來SQL Server不具備遞歸CTE的（或者語法是不同的）的search depth/breadth first條款。在任何情況下，這裏是一個原始的 「手冊」 執行相同的：

with ( ......... ), 
    r (lvl, location, ord) as (
     select 1, location, location 
     from inputs 
     where parent = 'Downstream' 
     union all 
     select r.lvl + 1, i.location, r.location || '/' || i.location 
     from r join inputs i on r.location = i.parent 
    ) 
select lpad(' ', 2 * (lvl-1), ' ') || location as location 
from r 
order by ord 
; 

Answer 2

繼mathguy提出的查詢，修改MSSQL（2012）

with 
     inputs (location, parent) as (
      select 'A001' , 'StartPoint' union all 
      select 'A002' , 'A001'  union all 
      select 'A003' , 'A002'  union all 
      select 'A004' , 'A002'  union all 
     select 'A004B', 'A004'  union all 
     select 'B005' , 'StartPoint' 
    ), 
    r (lvl, location, ord) as (
     select 1, location, CAST(location AS VARCHAR(400)) 
     from inputs 
     where parent = 'StartPoint' 
     union all 
     select r.lvl + 1, i.location, CAST(r.location + '/' + i.location AS VARCHAR(400)) 
     from r join inputs i on r.location = i.parent 
    ) 
select REPLICATE(' ', 2 * (lvl-1)) + location as location 
from r 
order by ord 
; 

輸出繼電器：

location 
------------------------------------------------------------------- 
A001 
    A002 
    A003 
    A004 
     A004B 
B005