我被要求這樣做,但我不知道是否有這樣做的標準方式。有誰知道是否有方法在SQL Server中導出?是否可以將我的SQL複製定義導出到XML?
0
A
回答
1
AFIK沒有這樣做的標準方法。作爲技術的複製早於XML,其工具集和元數據不是以XML爲中心的。但是,與複製相關的所有內容都存儲在表的某處,無論是在主數據庫還是在msdb或分發數據庫中,請參見Replication Tables topic on MSDN或複製DMV(sys.dm_repl_articles
和sys.dm_repl_schema
s)。所有這些信息都可以用XML格式化和格式化,但我不知道覆蓋這些信息的任何標準XML模式。
0
Remus的回答非常好。這是我用來將它導出到XML的SQL腳本。希望它對其他人有用:
DECLARE @PublicationId INT
SET @PublicationId = 1 –- Use your publication ID here. Use SELECT * FROM syspublications to see a list of publications
select
Publication.name AS [Name]
, Publication.description AS [Description]
, Article.name AS [Name]
, Article.dest_table AS [Table]
, [Column].name AS [Name]
, [Column].[Type]
, [Column].MaxLength
, [Column].Nullable
from dbo.syspublications Publication
join dbo.sysarticles Article on Publication.pubid = Article.pubid
join sys.tables st on st.object_id = Article.objid
join dbo.sysarticlecolumns ac on Article.artid = ac.artid
join
(
select
sc.object_id
, sc.column_id
, sc.name AS [Name]
, sty.name AS [Type]
, sc.max_length AS MaxLength
, sc.is_nullable AS Nullable
from dbo.syspublications p
join dbo.sysarticles a on p.pubid = a.pubid
join dbo.sysarticlecolumns ac on a.artid = ac.artid
join sys.columns sc on sc.object_id = a.objid AND sc.column_id = ac.colid
join sys.types sty on sty.user_type_id = sc.user_type_id
where p.pubid = @PublicationId
) [Column] on [Column].object_id = Article.objid AND [Column].column_id = ac.colid
where Publication.pubid = @PublicationId FOR XML AUTO
您能否定義您的定義是什麼意思?例如,你的意思是你的SQL Server複製配置的細節? – 2009-06-30 20:40:00