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我是新來的JPA加入表自定義,我想使用API標準,以創建這個查詢:JPA標準:草案第
SELECT company.*
FROM company
LEFT OUTER JOIN address ON company.id = address.company_id AND address.postal_code = '54000'
ORDER BY company.id;
搜索和反思之後,我嘗試這個代碼,這似乎是合乎邏輯我說:
...
CriteriaQuery<Company> query = criteriaBuilder.createQuery(Company.class)
Root<Company> defCompany = query.from(Company.class);
Join joinAddresses = defCompany.join("addresses", JoinType.LEFT);
joinAddresses.on(criteriaBuilder.equal(joinAddresses.get("postalCode"), "54000"));
query.orderBy(criteriaBuilder.asc(defCompany.get("id")));
List<Company> companies = entityManager.createQuer(query)
.getResultList();
...
但OpenJPA中拋出這個錯誤:
ERROR OpenEJB- EjbTransactionUtil.handleSystemException: org.apache.openjpa.persistence.criteria.Joins$List.on(Ljavax/persistence/criteria/Expression;)Ljavax/persistence/criteria/Join;
java.lang.AbstractMethodError: org.apache.openjpa.persistence.criteria.Joins$List.on(Ljavax/persistence/criteria/Expression;)Ljavax/persistence/criteria/Join;
我希望有人嘗試過這樣做,我覺得p可以,但我找不到關於此的線索或問題。
這就是它與Hibernate 5.2.5一起使用。照顧https://hibernate.atlassian.net/browse/HHH-2772。非常感謝 :) –