我想獲得按日期降序排序的數據,但始終我與ASC得到它, 我嘗試2種方式,但沒有好的結果:順序按日期字段在Spring數據JPA不工作
我有這個資源庫:
@Repository
public interface CollectRepository extends JpaRepository<Collect, Long>
1的方式,我以前在@query排序:
@Query("SELECT c FROM Collect c LEFT JOIN c.payee p WHERE p.userId=:userId AND c.date BETWEEN :startDate AND :endDate ORDER BY c.date DESC")
List<Collect> getCollectionHistory(@Param("userId") String userId,
@Param("startDate") Date startDate,
@Param("endDate") Date endDate);
第二個辦法,我用了排序
@Query("SELECT c FROM Collect c LEFT JOIN c.payee p WHERE p.userId=:userId AND c.date BETWEEN :startDate AND :endDate")
List<Collect> getCollectionHistory(@Param("userId") String userId,
@Param("startDate") Date startDate,
@Param("endDate") Date endDate, Sort sort);
,並呼籲使用功能:
@Entity
@Table(name = "payee")
@SequenceGenerator(name = "SEQ", sequenceName = "payee_id_seq", allocationSize = 1)
@AttributeOverride(name = "id", column = @Column(name = "payee_id", nullable = false))
public class Payee extends GenericEntity {
private String userId;
@OneToMany(mappedBy = "payee", cascade = CascadeType.ALL)
private List<Collect> collects;
@OneToMany(mappedBy = "payee", cascade = CascadeType.ALL, fetch = FetchType.EAGER)
private List<PayeePayer> payeePayers;
我使用Spring JPA的數據版本:1.10.5
collectionList = collectRepository.getCollectionHistoryByCollector(userId, startDate, endDate, new Sort(Direction.DESC, "date"));
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@Entity
@Table(name = "collect")
@SequenceGenerator(name = "SEQ", sequenceName = "collect_id_seq", allocationSize = 1)
@AttributeOverride(name = "id", column = @Column(name = "collect_id", nullable = false))
public class Collect extends GenericEntity {
@Column(name = "collector_user_id")
private String collectorUserId;
@ManyToOne(fetch = FetchType.EAGER)
@JoinColumn(name = "payer")
private Payer payer;
@ManyToOne(fetch = FetchType.EAGER)
@JoinColumn(name = "payee")
private Payee payee;
@Column(name = "amount", precision = 5)
private BigDecimal amount;
@Column(name = "date", columnDefinition = "TIMESTAMP DEFAULT CURRENT_TIMESTAMP")
@JsonSerialize(using = IsoDateSerializer.class)
private Date date;
@Column(name = "reason")
private String reason;
@Column(name = "reference")
private String reference;
// getters and setters
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這是一個錯誤還是我的代碼有問題? 我該如何解決這個問題?
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哪裏是你的用戶id的代碼? – xenteros