整數錯誤代碼

Question

我想寫一些代碼，將計算不同車牌號，正確格式和不正確的汽車的速度。該程序將在單獨的文本文件中打印速度不正確的汽車。這是我剛剛得到了錯誤，我對如何解決它不知道：

import re 
distance = 200 
speedlimit = 50 
nonstandardReg = open("text.txt ","w") 

userinput = input("Choose a car number 1 to 5") 
if userinput ==('1')or(' 1')or('car1')or(' car1'): 
car1 = "AD 12DER, 12:36:01, 12:36:40" 
elif userinput ==('2')or(' 2')or('car2')or(' car2'): 
car2 = "DE 61FE1, 02:47:01, 02:47:30" 
elif userinput == ('3')or(' 3')or('car3')or(' car3'): 
car3 = "AF 012GL, 04:08:32, 07:32:28" 
elif userinput == ('4')or(' 4')or('car4')or(' car4'): 
car4 = "TG 043WE, 08:45:23, 12:14:56" 
elif userinput == ('5')or(' 5')or('car5')or(' car5'): 
car5 = "TL 12AWY" 
else: 
print("Invalid Car") 
car1Time1 =int(car1[16:18]) 
car1Time2 =int(car1[26:28]) 
car1TimeEnd = car1Time2-car1Time1 
car1Speed = distance/car1TimeEnd 

car2Time1 =int(car2[16:18]) 
car2Time2 =int(car2[26:28]) 
car2TimeEnd = car2Time2-car2Time1 
car2Speed = distance/car2TimeEnd 

car3Time1 =int(car3[16:18]) 
car3Time2 =int(car3[26:28]) 
car3TimeEnd = car3Time2-car3Time1 
car3Speed = distance/car3TimeEnd 

car4Time1 =int(car4[16:18]) 
car4Time2 =int(car4[26:28]) 
car4TimeEnd = car4Time2-car4Time1 
car4Speed = distance/car4TimeEnd 

car5Time1 =int(car5[16:18]) 
car5Time2 =int(car5[26:28]) 
car5TimeEnd = car5Time2-car5Time1 
car5Speed = distance/car5TimeEnd 

這是錯誤我得到：

car2Time1 =(int(car2[16:18])) 
ValueError: invalid literal for int() with base 10: '' 

Answer 1

從您的意見，這聽起來像你不是確定你想要程序做什麼。這是可能的，你正在尋找的東西是這樣的：

if userinput ==('1')or userinput ==(' 1')or userinput ==('car1')or userinput ==(' car1'): 
car = "AD 12DER, 12:36:01, 12:36:40" 
elif userinput ==('2')or userinput ==(' 2')or userinput ==('car2')or userinput ==(' car2'): 
car = "DE 61FE1, 02:47:01, 02:47:30" 
elif userinput == ('3')or userinput ==(' 3')or userinput ==('car3')or userinput ==(' car3'): 
car = "AF 012GL, 04:08:32, 07:32:28" 
elif userinput == ('4')or userinput ==(' 4')or userinput ==('car4')or userinput ==(' car4'): 
car = "TG 043WE, 08:45:23, 12:14:56" 
elif userinput == ('5')or userinput ==(' 5')or userinput ==('car5')or userinput ==(' car5'): 
car = "TL 12AWY" 
else: 
print("Invalid Car") 
carTime1 =int(car[16:18]) 
carTime2 =int(car[26:28]) 
carTimeEnd = carTime2-carTime1 
carSpeed = distance/carTimeEnd 

現在，如果他們試圖使用car5，你會因爲你縮短一個不包括定時信息有問題。

Answer 2

您的代碼有幾個問題。首先，這種情況

if userinput ==('1')or(' 1')or('car1')or(' car1'): 

將始終評估爲True。您應該使用

if userinput ==('1') or userinput==(' 1') or userinput==('car1') or userinput == (' car1'): 

改爲。以此類推elif陳述。然後，你只需要一個car變量：

if userinput ==('1') or userinput==(' 1') or userinput==('car1') or userinput == (' car1'): 
car = "AD 12DER, 12:36:01, 12:36:40" 
... 
elif userinput ==('5') or userinput==(' 5') or userinput==('car5') or userinput == (' car5'): 
car = "TL 12AWY" 
else: 
print("Invalid Car") 
carTime1 =int(car[16:18]) 
carTime2 =int(car[26:28]) 
carTimeEnd = carTime2-carTime1 
carSpeed = distance/carTimeEnd 

而你需要適當地初始化爲car5 car變量。

Answer 3

我不太確定這段代碼對你有幫助，但你應該重新設計你的代碼，除非它很難找到錯誤。

car_dict={ 

'car1': "AD 12DER, 12:36:01, 12:36:40", 
'car2': "DE 61FE1, 02:47:01, 02:47:30", 
'car3': "AF 012GL, 04:08:32, 07:32:28", 
'car4': "TG 043WE, 08:45:23, 12:14:56", 
'car5': "TL 12AWY" 
} 

def speed_calculator(st, distance =200): 
    start_time= int(st[16:18]) 
    end_time= int(st[26:28]) 
    time_in_between = end_time - start_time 
    return distance/time_in_between 

userinput = raw_input("Choose a car number 1 to 5").strip() 


for key in car_dict: 
    if userinput in key: 
     print speed_calculator(car_dict[key])