如何解決，找出兩個的各個環節（Beautifulsoup，蟒蛇）

Question

即時通訊使用beautifulsoup4解析網頁，並使用此代碼

#Collect links from 'new' page 
pageRequest = requests.get('http://www.supremenewyork.com/shop/all/shirts') 
soup = BeautifulSoup(pageRequest.content, "html.parser") 
links = soup.select("div.turbolink_scroller a") 

allProductInfo = soup.find_all("a", class_="name-link") 
print allProductInfo 

linksList1 = [] 
for href in allProductInfo: 
    linksList1.append(href.get('href')) 

print(linksList1) 

linksList1打印兩各環節的收集所有的HREF值。我相信這是因爲它從標題以及項目顏色中獲取鏈接。我已經嘗試了一些東西，但不能讓BS只解析標題鏈接，並且每個鏈接都有一個列表，而不是兩個鏈接。我想象它真的很簡單，但我很想念它。在此先感謝

Answer 1

alldiv = soup.findAll("div", {"class":"inner-article"}) 
for div in alldiv: 
    linkList1.append(div.h1.a['href']) 

Answer 2

這個代碼將會給你的結果沒有得到重複結果 （也使用set（）可能是一個好主意，因爲@Tarum古普塔） 但我改變了你爬

import requests 
from bs4 import BeautifulSoup 

#Collect links from 'new' page 
pageRequest = requests.get('http://www.supremenewyork.com/shop/all/shirts') 
soup = BeautifulSoup(pageRequest.content, "html.parser") 
links = soup.select("div.turbolink_scroller a") 

# Gets all divs with class of inner-article then search for a with name-link class 
that is inside an h1 tag 
allProductInfo = soup.select("div.inner-article h1 a.name-link") 
# print (allProductInfo) 

linksList1 = [] 
for href in allProductInfo: 
    linksList1.append(href.get('href')) 

print(linksList1) 

Answer 3

set(linksList1)  # use set() to remove duplicate link 
list(set(linksList1)) # use list() convert set to list if you need