0
我正在嘗試編寫一個軟件，它將有一個視頻播放器，轉錄本並同步運行它們。無法從XML文件中提取時間數據
我現在對轉錄本有問題。我重視我使用的XML文件：
NodeList nodeParagraphs = root.getElementsByTagName("u");
NodeList nodeParagraphs2 = root.getElementsByTagName("internal-media");
for(int i=0; i < nodeParagraphs.getLength(); i++){
Element nodeParagraph = (Element)nodeParagraphs.item(i);
Element nodeParagraph2 = (Element)nodeParagraphs2.item(i);
String id = nodeParagraph.getAttribute("uID");
String who = nodeParagraph.getAttribute("who");
String Time = nodeParagraph2.getAttribute("start");
Paragraph p = new Paragraph(who, id, Time);
NodeList wNodeList = nodeParagraph.getElementsByTagName("w");
for(int j=0; j < wNodeList.getLength(); j++){
Element wElem = (Element)wNodeList.item(j);
String word = wElem.getTextContent();
p.addWord(word);
}
chat.addParagraph(p);
}
的問題是，當我顯示的成績單，他們是在錯誤的時間，因爲在每一個u節多個內部媒體標籤打印。當我只需要每個段落的第一個時，它將全部採用。示例如下所示：
<?xml version="1.0" encoding="UTF-8"?>
<CHAT xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns="http://www.talkbank.org/ns/talkbank"
xsi:schemaLocation="http://www.talkbank.org/ns/talkbank http://talkbank.org/software/talkbank.xsd"
Media="future" Mediatypes="video"
PID="11312/t-00017262-1"
Font="CAfont:13:0"
Version="2.2.1"
Lang="eng"
Options="CA"
Corpus="DaCapo"
Date="1984-01-01">
<Participants>
<participant
id="DAC"
name="Dacapo_Leader"
role="Adult"
language="eng"
/>
<participant
id="MIC"
name="Michael"
role="Adult"
language="eng"
/>
<participant
id="LUI"
name="Luis"
role="Adult"
language="eng"
/>
<participant
id="NIN"
name="Nina"
role="Adult"
language="eng"
/>
<participant
id="KEN"
role="Adult"
language="eng"
/>
<participant
id="JAK"
name="Jakob"
role="Adult"
language="eng"
/>
<participant
id="XXX"
role="Unidentified"
language="eng"
/>
<participant
id="WOM"
name="Dacapo_Woman"
role="Adult"
language="eng"
/>
</Participants>
<u who="KEN" uID="u0">
<w>as</w>
<w>it</w>
<w>currently</w>
<w>stands</w>
<w>one</w>
<w>of</w>
<w>the</w>
<w>things</w>
<w>that</w>
<w>people</w>
<w>do</w>
<internal-media
start="0.000"
end="2.520"
unit="s"
/>
<w>is</w>
<w>create</w>
<internal-media
start="2.520"
end="3.240"
unit="s"
/>
<w>one</w>
<w>of</w>
<w>the</w>
<w>things</w>
<w>that</w>
<w>anthropologists</w>
<w>design</w>
<w>researchers</w>
<w>do</w>
<internal-media
start="3.240"
end="6.720"
unit="s"
/>
<w>is</w>
<w>they</w>
<w>create</w>
<w>distance</w>
<w>between</w>
<w>business</w>
<w>people</w>
<internal-media
start="6.720"
end="9.160"
unit="s"
/>
<w>and</w>
<w>uh</w>
<t type="missing CA terminator"></t>
<media
start="9.160"
end="11.200"
unit="s"
/>
</u>
<u who="DAC" uID="u1">
<w>participants</w>
<t type="missing CA terminator"></t>
<media
start="11.200"
end="11.800"
unit="s"
/>
</u>
你能發佈XML文件（或樣本）？ –
@James_D對不起，我忘了添加它，我找不到如何上傳文件，所以我不得不將其添加爲Html snipit XD –
只需將其粘貼並[格式化爲代碼]（http：// meta。 stackexchange.com/questions/22186/how-do-i-format-my-code-blocks） –