如何在Selenium中隨機點擊鼠標（從不相同的元素）？

Question

我想隨機點擊Windows 10 python 3.下面的代碼工作，除非它不是隨機點擊元素。它也以一種可笑的速度點擊。爲了試圖阻止這個，我添加了time.sleep（3），但是這往往會使它失敗，並且給出一個沒有這個睡眠命令就不存在的錯誤。所有元素似乎已經加載。看到錯誤信息與睡眠：https://ibb.co/cUYL45

 import time 
     from selenium import webdriver 
     from random import randint 

     driver = webdriver.Chrome(executable_path=r'C:\Brother\chromedriver.exe') 
     driver.set_window_size(1024, 600) 
     driver.maximize_window() 

     time.sleep(4) 

     driver.get('https://www.unibet.com.au/betting#drill-down/football') 


     time.sleep(10) 
     links = driver.find_elements_by_css_selector('.KambiBC-drill-down-navigation__toggle') 
    #Not randomising?? 
     l = links[randint(0, len(links)-1)] 
     for l in links: 
      l.click() 
#Tends to give error when I have a sleep command but it's goes way to fast not to have it. 
#All elements have already loaded so explicit not needed.. 
      time.sleep(5) 
      ... 


     time.sleep(5) 



     driver.close() 

Answer 1

如果你想點擊隨機元素（從隨機索引列表元素）你可以嘗試

l = links[randint(0, len(links)-1)] 
l.click() 

，而不是

l = links[randint(0, len(links)-1)] 
for l in links: 
    l.click() 

請注意0​​在l = links[randint(0, len(links)-1)]和l在for l in links是不同的變量

如果你想每次從下拉新option元素點擊，你可以試試下面：

from random import shuffle 
from selenium.webdriver.support.ui import WebDriverWait as wait 
from selenium.webdriver.common.by import By 
from selenium.webdriver.support import expected_conditions as EC 
from selenium import webdriver as web 

driver = web.Chrome() 
driver.get('https://ubet.com/sports/soccer') 

options = driver.find_elements_by_xpath('//select[./option="Soccer"]/option') 

# Get list of inetegers [1, 2, ... n] 
indexes = [index for index in range(len(options))] 
# Shuffle them 
shuffle(indexes) 
for index in indexes: 
    # Click on random option 
    wait(driver, 10).until(
     EC.element_to_be_clickable((By.XPATH, '(//select[./option="Soccer"]/option)[%s]' % str(index + 1)))).click()