如何在角度中使用絕對URL獲取$ state

Question

我試圖獲取$state的URL。

基本上我想要做反向的：

$state.href('user.home.view', {}, {absolute: true}); 

而是獲取Abs URL我想獲得該州的名字;

我想通過一個Abs URL到一個函數，然後在angular的項目中獲得一個有效的$state。

Answer 1

有一個名爲$uiView的數據字段附加到ui-view元素，它包含視圖名稱和關聯的狀態。你可以得到這樣的狀態：

elem.closest('[ui-view]').data('$uiView').state 

甚至

elem.inheritedData('$uiView').state 

所以，在你的控制器：

.controller('State1Ctrl', function ($state) { 
     console.log(elem.closest('[ui-view]').data('$uiView').state); // state1 
     console.log($state.current.name) ;//will give the state name as well. 
}); 

UPDATE：

Your issue:https://github.com/angular-ui/ui-router/issues/1651

解決方法：
ANGULAR-UI-ROUTER: Resolve state from URL

您可以通過使用.decorator鉤上$stateProvider暴露內部狀態的實現。你可以裝飾國家建設者的任何財產;有人選擇'parent'任意。

app.config(function($stateProvider) { 
    $stateProvider.decorator('parent', function (internalStateObj, parentFn) { 
    // This fn is called by StateBuilder each time a state is registered 

    // The first arg is the internal state. Capture it and add an accessor to public state object. 
    internalStateObj.self.$$state = function() { return internalStateObj; }; 

    // pass through to default .parent() function 
    return parentFn(internalStateObj); 
    }); 
}); 

現在你可以使用。$$ state（）方法來訪問內部狀態對象。

var publicState = $state.get("foo"); 
    var privateInternalState = publicState.$$state(); 
    //Second, loop over each state in $state.get() and test them against your URL fragment. 

    angular.forEach($state.get(), function(state) { 
     var privatePortion = state.$$state(); 
     var match = privatePortion.url.exec(url, queryParams); 
     if (match) console.log("Matched state: " + state.name + " and parameters: " + match); 
    });