2
我使用的是boost序列化,主要是侵入式版本。對於一個模板Matrix類我想有這對Visual Studio的工作原理與下面的代碼non-intrusive version:模板類的非侵入式序列化方法
namespace boost
{
namespace serialization
{
template<class Archive, int R, int C, class ElementType>
void serialize(Archive & ar, Matrix<R, C, ElementType> & m, const unsigned int version)
{
ar & ...
}
}
}
int R
,int C
是該行和列,ElementType
是double
或float
。
但是,這不會對GCC 4.3.2錯誤
error: 'class Matrix<1u, 3u, double>' has no member named 'serialize'
如果我用一種特殊的形式像
namespace boost
{
namespace serialization
{
template<class Archive>
void serialize(Archive & ar, Matrix<3,1,double> & m, const unsigned int version)
{
ar & ...
}
}
}
它編譯於GCC,當然只爲工作特殊的模板參數集。
我該怎麼做才能使它在所有的編譯器上都能工作R
,C
和ElementType
?
編輯:這些都是導致錯誤的線:
/[myfolder]/lib/BOOST/1_44_0/include/boost/serialization/access.hpp: In static member function 'static void boost::serialization::access::serialize(Archive&, T&, unsigned int) [with Archive = boost::archive::binary_iarchive, T = Matrix<3u, 1u, double>]':
/[myfolder]/lib/BOOST/1_44_0/include/boost/serialization/serialization.hpp:70: instantiated from 'void boost::serialization::serialize(Archive&, T&, unsigned int) [with Archive = boost::archive::binary_iarchive, T = Matrix<3u, 1u, double>]'
/[myfolder]/lib/BOOST/1_44_0/include/boost/serialization/serialization.hpp:129: instantiated from 'void boost::serialization::serialize_adl(Archive&, T&, unsigned int) [with Archive = boost::archive::binary_iarchive, T = Matrix<3u, 1u, double>]'
/[myfolder]/lib/BOOST/1_44_0/include/boost/archive/detail/iserializer.hpp:182: instantiated from 'void boost::archive::detail::iserializer<Archive, T>::load_object_data(boost::archive::detail::basic_iarchive&, void*, unsigned int) const [with Archive = boost::archive::binary_iarchive, T = Matrix<3u, 1u, double>]'
你如何調用序列化方法? – LumpN 2011-03-29 09:06:51
助推器,請參閱我的編輯。 – Philipp 2011-03-29 09:53:14
哪個版本的GCC? – 2011-03-29 10:19:35