使用Python解析文本正則表達式re.findall

Question

我有一個很長的字符串，我需要在組中進行解析，但需要更多地控制它。

import re 

RAW_Data = "Name Multiple Words Testing With 1234 Numbers and this stuff* ((Bla Bla Bla (Bla Bla) A40 & A41)) Name Multiple Words Testing With 3456 Numbers and this stuff2* ((Bla Bla Bla (Bla Bla) A42 & A43)) Name Multiple Words Testing With 78910 Numbers and this stuff3* ((Bla Bla Bla (Bla Bla) A44 & A45)) Name Multiple Words Testing With 1234 Numbers and this stuff4* ((Bla Bla Bla (Bla Bla) A46 & A47)) Name Multiple Words Testing With 1234 Numbers and this stuff5* ((Bla Bla Bla (Bla Bla) A48 & A49)) Name Multiple Words Testing With 1234 Numbers and this stuff6* ((Bla Bla Bla (Bla Bla) A50 & A51)) Name Multiple Words Testing With 1234 Numbers and this stuff7* ((Bla Bla Bla (Bla Bla) A52 & A53)) Name Multiple Words Testing With 1234 Numbers and this stuff8* ((Bla Bla Bla (Bla Bla) A54 & A55)) Name Multiple Words Testing With 1234 Numbers and this stuff9* ((Bla Bla Bla (Bla Bla) A56 & A57)) Name Multiple Words Testing With 1234 Numbers and this stuff10* ((Bla Bla Bla (Bla Bla) A58 & A59)) Name Multiple Words Testing With 1234 Numbers and this stuff11* ((Bla Bla Bla (Bla Bla) A60 & A61)) Name Multiple Words Testing With 1234 Numbers and this stuff12* ((Bla Bla Bla (Bla Bla) A62 & A63)) Name Multiple Words Testing With 1234 Numbers and this stuff13* ((Bla Bla Bla (Bla Bla) A64 & A65)) Name Multiple Words Testing With 1234 Numbers and this stuff14* ((Bla Bla Bla (Bla Bla) A66 & A67)) Name Multiple Words Testing With 1234 Numbers and this stuff15* ((Bla Bla Bla (Bla Bla) A68 & A69)) Name Multiple Words Testing With 1234 Numbers and this stuff16*" 

fromnode = re.findall('(.*?)(?=\*\s)', RAW_Data) 

print fromnode 

del fromnode 
del RAW_Data 

的結果是： '名稱多字測試使用1234號這東西'， ''，'（（唧唧歪歪（BLA BLA）A40 & A41））名稱多字測試使用3456號和這東西2'........等等。

我似乎無法捕捉到只有串像「名稱多字測試使用3456號這東西」，並省略都喜歡的琴絃「（（唧唧歪歪（BLA BLA）A40 A41 &）） 」。任何幫助將非常感激。

Answer 1

可以與

r'\*\s*\({2}.*?\){2}\s*' 

圖案（see demo）劃分相符：

• \* - 字面星號
• \s* - 零個或多個空格
• \({2} - 正好2開口圓括號
• 個.*? - 除換行符以外的零個或多個字符：儘可能少到第一
• \){2}（注意：如果你需要跨越幾行匹配添加re.S標誌） - 雙右括號
• \s* - 0+空白。

另外：same, but unrolled (thus, a bit more efficient) regex：

\*\s*\({2}[^)]*(?:\)(?!\))[^)]*)*\){2}\s* 

見IDEONE demo：

import re 
p = re.compile(r'\*\s*\({2}.*?\){2}\s*') 
test_str = "Name Multiple Words Testing With 1234 Numbers and this stuff* ((Bla Bla Bla (Bla Bla) A40 & A41)) Name Multiple Words Testing With 3456 Numbers and this stuff2* ((Bla Bla Bla (Bla Bla) A42 & A43)) Name Multiple Words Testing With 78910 Numbers and this stuff3* ((Bla Bla Bla (Bla Bla) A44 & A45)) Name Multiple Words Testing With 1234 Numbers and this stuff4* ((Bla Bla Bla (Bla Bla) A46 & A47)) Name Multiple Words Testing With 1234 Numbers and this stuff5* ((Bla Bla Bla (Bla Bla) A48 & A49)) Name Multiple Words Testing With 1234 Numbers and this stuff6* ((Bla Bla Bla (Bla Bla) A50 & A51)) Name Multiple Words Testing With 1234 Numbers and this stuff7* ((Bla Bla Bla (Bla Bla) A52 & A53)) Name Multiple Words Testing With 1234 Numbers and this stuff8* ((Bla Bla Bla (Bla Bla) A54 & A55)) Name Multiple Words Testing With 1234 Numbers and this stuff9* ((Bla Bla Bla (Bla Bla) A56 & A57)) Name Multiple Words Testing With 1234 Numbers and this stuff10* ((Bla Bla Bla (Bla Bla) A58 & A59)) Name Multiple Words Testing With 1234 Numbers and this stuff11* ((Bla Bla Bla (Bla Bla) A60 & A61)) Name Multiple Words Testing With 1234 Numbers and this stuff12* ((Bla Bla Bla (Bla Bla) A62 & A63)) Name Multiple Words Testing With 1234 Numbers and this stuff13* ((Bla Bla Bla (Bla Bla) A64 & A65)) Name Multiple Words Testing With 1234 Numbers and this stuff14* ((Bla Bla Bla (Bla Bla) A66 & A67)) Name Multiple Words Testing With 1234 Numbers and this stuff15* ((Bla Bla Bla (Bla Bla) A68 & A69)) Name Multiple Words Testing With 1234 Numbers and this stuff16*" 
print(re.split(p, test_str)) 

UPDATE

一種使用正則表達式與re.findall：

(?:\*\s*\(\([^)]*(?:\)(?!\))[^)]*)*\)\))?\s*([^*]*(?:\*(?!\s*\(\()[^*]*)*)\s* 

見regex demo

驚恐於它的外觀？它只是一個簡單得多的展開版本(?:\*\s*\(\(.*?\)\))?\s*(.*?(?=\*\s*(?:\(\(|$)))。

查看IDEONE demo。