Python：創建單詞分析

Question

我正在嘗試創建一個分析用戶輸入單詞的工具。它說明了字母的數量（完成），元音的數量（需要幫助），大寫字母的數量（已完成）以及最常見的字母（尚未擔心）。我也做了下面的代碼：

word = raw_input("Please enter a word:") 
print word 


if len(word) == 1: 
    print word + " has " + str(len(word)) + " letter." 
else: 
    print word + " has " + str(len(word)) + " letters." 


if sum(1 for v in word if v ==["a", "e", "i", "o", "u", "A", "E", "I", "O", "U"]) == 1: 
    print "It also has ", sum(1 for v in word if v == ["a", "e", "i", "o", "u", "A", "E", "I", "O", "U"]), " vowel." 
else: 
    print "It also has ", sum(1 for v in word if v == ["a", "e", "i", "o", "u", "A", "E", "I", "O", "U"]), " vowels." 


if sum(1 for c in word if c.isupper()) == 1: 
    print "It has ", sum(1 for c in word if c.isupper()), " capital letter." 
else: 
    print "It has ", sum(1 for c in word if c.isupper()), " capital letters." 

使用例如字「你好」，它返回如下：

HeLLo 
HeLLo has 5 letters. 
It also has 0 vowels. 
It has 3 capital letters. 

我很困惑，因爲它知道算元音的數量，包括它在答案中，卻沒有統計單詞中的元音。

我需要做一個小調整還是一個大的改變？

謝謝。

P.S.我如何將問題標記爲已回答？

Answer 1

您正在比較該信與列表。相反，請檢查該信是否爲in該列表。

sum(1 for v in word if v in ["a", more vowels, "U"]) 

此外，您可以通過使用一個字符串，而不是一個列表，並通過套管低信爲先，並沒有重複自己儘可能多的讓你的代碼稍短。

num_vowels = sum(1 for v in word if v.lower() in "aeiou") 
print "It also has ", num_vowels, (" vowel." if num_vowels == 1 else " vowels.") 

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爲了找到最常見的字母，你應該使用的字典。只要迭代單詞中的字母並增加它們在字典中的數量，然後選擇數量最高的字母。

counts = {} 
for x in word: 
    counts[x] = counts.get(x, 0) + 1 
print "most common:", max(word, key=lambda x: counts[x]) 

或者只是使用collections.Counter(word).most_common(1)