1
在調度-servlet.xml文件在彈簧MVC映射在web.xml多個URL模式休息控制器,我有以下配置如何使用瓦片
<bean id="viewResolver"
class="org.springframework.web.servlet.view.UrlBasedViewResolver">
<property name="viewClass"
value="org.springframework.web.servlet.view.tiles3.TilesView" />
</bean>
<bean id="tilesConfigurer"
class="org.springframework.web.servlet.view.tiles3.TilesConfigurer">
<property name="definitions">
<list>
<value>/WEB-INF/tiles.xml</value>
</list>
</property>
</bean>
彈簧security.xml文件文件
<http auto-config="true" use-expressions="true">
<intercept-url pattern="/resources/**" access="true" />
<intercept-url pattern="/login.htm" access="true" />
<intercept-url pattern="/postSocialResponse.htm" access="true" />
<intercept-url pattern="/rest/socialData/*" access="true" />
<intercept-url pattern="/**" access="hasAnyRole('ROLE_SA','ROLE_ADMIN', 'ROLE_LEAD','ROLE_AGENT')" />
<form-login
login-page="/login.htm"
default-target-url="/"
authentication-failure-url="/login.htm?error"
username-parameter="username"
password-parameter="password" />
<logout logout-success-url="/login.htm?logout" />
web.xml文件
<servlet>
<servlet-name>socialcare-dispatcher</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>socialcare-dispatcher</servlet-name>
<url-pattern>*.htm</url-pattern>
</servlet-mapping>
GetSocialAnalyzedDataService.java文件
@RestController
@RequestMapping(value="/rest/socialData")
public class GetSocialAnalyzedDataService {
private Logger logger = LoggerFactory.getLogger(getClass());
private static SocialAnalyzedDataRepository socialAnalyzedDataRepository= SocialAnalyzedRepositoryImpl.getInstance();
@RequestMapping(value = "/{feedPostUserId}", method = RequestMethod.GET)
public @ResponseBody String createMessage(@PathVariable String feedPostUserId) throws Exception {
logger.info("feedpost user id"+feedPostUserId);
return feedPostUserId;
}
}
誰能幫我打電話給使用上面的配置文件這個URL。 我不能與http://localhost:8080/FilterRule/rest/socialData/create.htm然後用URL模式http://localhost:8080/FilterRule/rest/socialData/234567
訪問Web服務。如果我使用下面的代碼,它正在
@RequestMapping(value="/rest/socialData")
public class GetSocialAnalyzedDataService {
private Logger logger = LoggerFactory.getLogger(getClass());
private static SocialAnalyzedDataRepository socialAnalyzedDataRepository= SocialAnalyzedRepositoryImpl.getInstance();
@RequestMapping(value = "/create.htm", method = RequestMethod.GET)
public @ResponseBody String createMessage() throws Exception {
logger.info("feedpost user id");
return feedPostUserId;
}
}
感謝Ootero的迴應。但是,如果我正在編寫上面的代碼,那麼我得到的錯誤。在此行發現多個註釋: \t - cvc-identity-constraint.4.1:爲身份約束聲明重複的唯一值[socialcare-dispatcher]「web-app- servlet-name-uniqueness「 \t元素」web-app「。 \t \t socialcare1-調度 servlet的名稱> \t \t org.springframework.web.servlet.DispatcherServlet servlet的: –
user6209247
因此,我已用下面的代碼解決了它-class> \t \t <負載上啓動> 2負載上啓動> \t \t \t \t socialcare1-調度 servlet的名稱> \t \t /rest/ url-pa ttern> \t \t \t servlet-mapping> –
user6209247