從PHP中的數組中檢查上傳文件類型。

Question

如何檢查文件擴展名和MIME類型是否在數組中，這是我目前擁有的代碼。

$upload_project_thum = $_FILES['upload_project_thum']['name']; 
$upload_project_thum_ext = substr($upload_project_thum, strrpos($upload_project_thum, '.') + 1);  
$upload_permitted_types= array('image/jpeg:jpg','image/pjpeg:jpg','image/gif:gif','image/png:png'); 

然後倒在那裏我檢查，如果該文件是一個有效的類型我有這樣的foreach循環

foreach ($upload_permitted_types as $image_type) { 
     $type = explode(":", $image_type); 
      if (($type[0] != $_FILES['upload_project_thum']['type']) && ($upload_project_thum_ext != $type[1])) { 
       $errmsg_arr[] = 'Please select a jpg, jpeg, gif, or png image to use as the project thumbnail'. $type[1] . " Type: ". $type[0]; 
       $errflag = true; 
     } 

的問題是，如果文件類型是不是所有的類型的數組（這是不可能的）我得到一個錯誤。它的工作原理是，如果上傳文件位於數組中，則錯誤消息不會觸發。

Answer 1

我現在這樣做的方法是：

$upload_permitted_types['mime']= array('image/jpeg','image/gif','image/png'); 
$upload_permitted_types['ext']= array('jpeg','jpg','gif','png'); 

if(!in_array($_FILES['upload_project_thum']['type'],$upload_permitted_types['mime']) || !in_array($upload_project_thum_ext,$upload_permitted_types['ext']) 
{ 
     $errmsg_arr[] = 'Please select a jpg, jpeg, gif, or png image to use as the project thumbnail'; 
     $errflag = true; 
} 

到這樣做的好處是，它可以讓一個.gif文件與jpeg的啞劇。因此它不會強制我的地圖和擴展名匹配，但確保它們都是圖像類型。

Answer 2

if (!in_array($_FILES['upload_project_thum']['type'], $upload_permitted_types)){ 

    exit("Unsupported file type"); 
} 

Answer 3

if(!in_array($_FILES['upload_project_thum']['type'] . ':' . $upload_project_thum_ext, $upload_permitted_types)) { 
    Trigger-error-here; 
} 

這應該從兩個類型和擴展粘適當的字符串。

另一種方法是修改你的循環這樣的：

$is_allowed = false; 
foreach ($upload_permitted_types as $image_type) { 
    $type = explode(":", $image_type); 
    if (($type[0] == $_FILES['upload_project_thum']['type']) && ($type[1] == $upload_project_thum_ext)) { 
     $is_allowed = true; 
     break; 
    } 
} 

if(!$is_allowed) { 
     $errmsg_arr[] = 'Please select a jpg, jpeg, gif, or png image to use as the project thumbnail'. $type[1] . " Type: ". $type[0]; 
     $errflag = true; 
} 

Answer 4

我希望得到的文件數組，然後用在可能的條件下

$is_error = TRUE; 

$allowFileTypes = array(
      "image/png","image/jpg","image/jpeg" 
     ); 

$UserBaseFolder = 'userfiles/'.$_SESSION['user_id']; 
      if(!file_exists($UserBaseFolder)) { 
      mkdir("userfiles/".$_SESSION['user_id']."/"); 
     } 



    if ($_FILES['file']['error'] === UPLOAD_ERR_OK) { 
     foreach($_FILES as $dat => $f) { 
       if($f['size'] == "0") { 
        $msg .= '<p><span class="alert alert-danger">You must upload a file.</span></p>'; 
        $is_error = FALSE; 
       } 

       if($f['size'] > "2000000") { 
        $msg .= '<p><span class="alert alert-danger">Your file size is too big.</span></p>'; 
        $is_error = FALSE; 
       } 


       if(!in_array($f['type'],$allowFileTypes)){ 
        $msg .= '<p><span class="alert alert-danger">Your file has invalid format. Please try again...</span></p>'; 
        $is_error = FALSE; 
       } else { 
       $filepath = $UserBaseFolder.'/'.time().'-'.$f['name']; 
       move_uploaded_file($f["tmp_name"], $filepath); 
       } 

回報$味精foreach循環literating;