我正在使用CodeIgniter並且在數據庫中遇到了一些問題。我使用數據庫中的表'客戶'的客戶名填充我的下拉列表。我需要從下拉列表中選擇名稱,以輸入項目名稱並將其添加到數據庫表「項目」中,但在此表中,我不應該有客戶的名稱,而是其ID。我該如何執行它?而當我想發送不是id,但名稱 - 我有一個錯誤:該customerName具有NULL值。dropdown value to db codeigniter
Here is my controller
<?php if (! defined('BASEPATH')) exit('No direct script access allowed');
class Add extends CI_Controller {
public function __construct() {
parent::__construct();
$this->load->helper(array('url', 'form'));
$this->load->model("addmodel");
$this->load->library('session');
}
private function view($page, $data=false) {
$this->load->view("header.php", $data);
$this->load->view($page, $data);
$this->load->view("footer.php", $data);
}
public function add_project() {
$this->load->database();
$data['customers']=$this->addmodel->select_customer();
$this->view('add/add_project.php', $data);
}
public function new_project() {
$this->load->database();
$data['customers']=$this->addmodel->select_customer();
$this->load->view("add/add_project.php", $data);
$projectName = $this->input->post("projectName");
$customerID = $this->input->post("customerName");
$this->addmodel->add_project($projectName, customerID);
redirect("add_project", "refresh");
}
}
Here is my model
<?php
class AddModel extends CI_Model {
public function __construct() {
$this->load->database();
}
function add_project($projectName, $customerID) {
$this->db->insert('projects', array(
'projectName' => $projectName,
'customerID' => $customerID
));
}
function select_customer() {
$query = $this->db->get('customers');
return $query;
}
}
?>
and, finally, here is my view
<?php echo form_open('new_project'); ?>
<div id="form-main">
<div id="form-div">
<form class="form" id="form1">
<select class="feedback-input" id="customer_selecter">
<option name="customerName">Select customer</option>
// <?php
foreach($customers->result() as $row){
echo '<option value="'.$row->customerID.'">'.$row->customerName.'</option>';
}
?>
</select>
<p class="projectName">
<input type="text" name="projectName" placeholder="Project name" required class="feedback-input" id="projectName" />
</p>
<div class="submit">
<button type="submit" id="button-red">Add</button>
<div class="ease"></div>
</form>
</div>
</form>
</div>
您的問題律混亂,那你真正想要做什麼? – chigs
'$ this-> addmodel-> add_project($ projectName,customerID);'應該是'$ this-> addmodel-> add_project($ projectName,$ customerID);'你忘了'$' –
我想發送到db在下拉 – Ksenia