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我嘗試通過AJAX WagonAvaliableResponse發送對象的方法。當我測試這個得到錯誤類型錯誤:WagonAvaliableResponse不是一個函數如何通過jQuery與jQuery發送對象?
如何解決這一問題?
var WagonAvaliableResponse = {
UniqId:'',
checksum:'',
FromStation:0,
ToStation:0,
MainUniqId:0.0,
compartmentCapicityField:'',
isCompartmentField:'',
circularNumberSerialField:'',
countingAllField:'',
rateCodeField:0,
airConditioningField:false,
mediaField:false,
timeOfArrivalField:'',
rationCodeField:0,
soldcountingField:0,
ownerField: ''
};
$('#Continue').click(function(e) {
e.preventDefault;
var obj = new WagonAvaliableResponse();
obj.Uniqid = $('#DepartureTrain article.show input[data=UniqId]').val();
obj.mainuniqId = $('input[name=MainUniqId]').val();
$.ajax({
url: '/Train/CheckValidSelection',
data: obj,
type: "POST",
success: function (result) {
alert(result.Message);
},
error: function() {
alert(result.Message);
}
});
});
刪除'var obj = new WagonAvaliableResponse();'。你已經聲明瞭這個對象,所以只需使用'WagonAvaliableResponse.Uniqid = ...'等等,然後在ajax函數中 - 'data:WagonAvaliableResponse,' –
好的。這是對的。 – programmer138200