-1
所以我有一個變量,需要顯示爲一天的時間,即3:02,然後使計算關閉該變量,即將7添加到第一個變量,惠靈頓,並顯示爲3:09。 這是一個簡單的問題,它不需要進入日期時間 有沒有一種方法可以做到這一點,沒有日期?試圖顯示一個變量作爲打印時間
def traintimes():
crofton = wellington + 7
ngaio = crofton + 2
awarua = ngaio + 2
simla = awarua + 2
boxhill = simla + 1
kandallah = boxhill + 2
raroa = kandallah + 2
johnsonville = raroa + 2
print ("Wellington:",wellington,"Crofton Downs:",crofton,"Ngaio:",ngaio,"Awarua Street:",awarua,"Simla Crescent:",simla,"Box Hill:",boxhill,"Kandallah:",kandallah,"Raroa:",raroa,"Johnsonville:",johnsonville)
wellington = int("3:02")
traintimes()
wellington = int("3:28")
traintimes()
wellington = int("3:40")
traintimes()
可能重複[在Python中爲datetime.time添加N秒的標準方式是什麼?](http://stackoverflow.com/questions/100210/what-is-the-standard-way-to-add -n-seconds-to-datetime-time-in-python) –