SELECT * FROM
(select
petID as pet,
sum(numpet) as numberofpets
from petTable) as base
pivot(
count(sum(numpet))
for petid IN ([1],[2],[3])
) AS pivottable
一直停留在這個語法錯誤一段時間:(口口聲聲說語法不正確附近 'numpet' 和([1],[2],[3])。誰能幫我?謝謝透視表期待 '('
SELECT * FROM
(select
petID as pet,
sum(numpet) as numberofpets
from petTable) as base
pivot(
count(sum(numpet))
for petid IN ([1],[2],[3])
) AS pivottable
一直停留在這個語法錯誤一段時間:(口口聲聲說語法不正確附近 'numpet' 和([1],[2],[3])。誰能幫我?謝謝透視表期待 '('
base
派生表numberofpets
場爲sum(numpet)
一個GROUP BY petID
條款。只是做COUNT(numberofpets)
對不起,您在基礎派生表中的GROUP by子句是什麼意思? – vanillacoke9191
在派生表中自行運行查詢,您將得到的錯誤就是我所指的。 –
使用錯過GROUP BY物理表的SELECT子句中:
SELECT * FROM
(
SELECT petID as pet,sum(numpet) as numberofpets
FROM petTable
GROUP BY petID
) base
pivot
(
COUNT(SUM(numpet)) FOR petid IN ([1],[2],[3])
) AS pivottable
哪個分貝是這樣嗎?提供一些信息,以便我們檢查 – Debabrata