2017-06-02 59 views
0

我想執行的每個從基類擴展類initialize()方法Execute方法一次,使用late static bindings每個子類

class BaseClass 
{ 
    protected static $initialized = false; 

    public static function find() 
    { 
     static::initialize(); 
     //TODO search entries and return as instances... 
    } 

    protected static function initialize() 
    { 
     if (static::$initialized) 
      return; 

     echo 'Initializing ', static::class, '<br/>'; 
     //do important stuff 
     static::$initialized = true; 
    } 
} 

class Child1 extends BaseClass {} 
class Child2 extends BaseClass {} 

$initialized屬性被整個擴展類共享。

Child1::find(); //Outputs 'Initializing Child1', as expected 
Child2::find(); //Doesn't execute 'initialize()' because 
       //$initialized property was set to true by Child1 
       //Expected: 'Initializing Child2' 

有沒有簡單的方法來實現它?

+0

改變'$ initialized'到一個數組,在其中添加初始化類,並檢查是否存在等帶有'in_array()'的(Child-)類 – dognose

回答

0

可以使用類名作爲鍵更改$初始化數組(如評論所說):

class BaseClass 
{ 
    protected static $initialized = []; 

    public static function find() 
    { 
     return static::initialize(); 
    } 

    protected static function initialize() 
    { 
     $class_name = static::class; 
     if (!empty(static::$initialized[$class_name])) { 
      return static::$initialized[$class_name]; 
     } 

     echo 'Initializing ', $class_name, '<br/>'; 
     //do important stuff 
     static::$initialized[$class_name] = new static(); 
     // do another important stuff and return instance 
     return static::$initialized[$class_name]; 
    } 
} 

class Child1 extends BaseClass {} 
class Child2 extends BaseClass {} 
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