我編譯該代碼(使用鐺3.4.2):這是LLVM中的錯誤嗎?
#include <stdlib.h>
#include <stdio.h>
#include <inttypes.h>
typedef struct __entry {
char *name;
int value;
} entry;
int main(int argv, char **argc) {
printf("Size of entry: %lu\n", sizeof(entry));
entry *entry = malloc(sizeof(entry));
printf("entry is at %lu\n", (uint64_t) entry);
}
和我收到此位碼:
define i32 @main(i32 %argv, i8** %argc) #0 {
entry:
%argv.addr = alloca i32, align 4
%argc.addr = alloca i8**, align 8
%entry1 = alloca %struct.__entry*, align 8
store i32 %argv, i32* %argv.addr, align 4
store i8** %argc, i8*** %argc.addr, align 8
%call = call i32 (i8*, ...)* @printf(i8* getelementptr inbounds ([20 x i8]* @.str, i32 0, i32 0), i64 16)
%call2 = call noalias i8* @malloc(i64 8) #3
%0 = bitcast i8* %call2 to %struct.__entry*
store %struct.__entry* %0, %struct.__entry** %entry1, align 8
%1 = load %struct.__entry** %entry1, align 8
%2 = ptrtoint %struct.__entry* %1 to i64
%call3 = call i32 (i8*, ...)* @printf(i8* getelementptr inbounds ([17 x i8]* @.str1, i32 0, i32 0), i64 %2)
ret i32 0
}
對printf的呼叫接收16作爲一個參數(我預期要結構與64位系統上的兩個指針)。但是,對malloc的調用會得到8.在C中,它們都得到了相同的參數。到底是怎麼回事?
程序運行時是否打印正確的值? – EOF
您的代碼調用未定義的行爲。 – Stargateur
該錯誤爲類型和對象重載了'entry'標識符。 – Jens