我用jQuery做了一個簡單的驗證表單。它工作正常。事情是我不滿意我的代碼。是否有另一種方法來編寫我的代碼具有相同的輸出結果?一個簡單的jQuery表單驗證腳本
$(document).ready(function(){
$('.submit').click(function(){
validateForm();
});
function validateForm(){
var nameReg = /^[A-Za-z]+$/;
var numberReg = /^[0-9]+$/;
var emailReg = /^([\w-\.][email protected]([\w-]+\.)+[\w-]{2,4})?$/;
var names = $('#nameInput').val();
var company = $('#companyInput').val();
var email = $('#emailInput').val();
var telephone = $('#telInput').val();
var message = $('#messageInput').val();
var inputVal = new Array(names, company, email, telephone, message);
var inputMessage = new Array("name", "company", "email address", "telephone number", "message");
$('.error').hide();
if(inputVal[0] == ""){
$('#nameLabel').after('<span class="error"> Please enter your ' + inputMessage[0] + '</span>');
}
else if(!nameReg.test(names)){
$('#nameLabel').after('<span class="error"> Letters only</span>');
}
if(inputVal[1] == ""){
$('#companyLabel').after('<span class="error"> Please enter your ' + inputMessage[1] + '</span>');
}
if(inputVal[2] == ""){
$('#emailLabel').after('<span class="error"> Please enter your ' + inputMessage[2] + '</span>');
}
else if(!emailReg.test(email)){
$('#emailLabel').after('<span class="error"> Please enter a valid email address</span>');
}
if(inputVal[3] == ""){
$('#telephoneLabel').after('<span class="error"> Please enter your ' + inputMessage[3] + '</span>');
}
else if(!numberReg.test(telephone)){
$('#telephoneLabel').after('<span class="error"> Numbers only</span>');
}
if(inputVal[4] == ""){
$('#messageLabel').after('<span class="error"> Please enter your ' + inputMessage[4] + '</span>');
}
}
});
是的,你可以使用jQuery驗證爲使腳本更好一些了。 – 2013-02-25 04:48:14
你能告訴我如何?他們說寫代碼就像寫詩一樣。我希望優化我的代碼。 – jhedm 2013-02-25 04:52:55
http://codereview.stackexchange.com/ - 這就是你要找的 – Alexander 2013-02-25 22:11:37