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我難以置信地堅持創建這個。我的計劃的想法是發揮誰想成爲百萬富翁，每個豆是每個問題。我正在指示servlet讀取bean並將問題和可能的答案發送給要顯示的JSP。用戶將通過超鏈接選擇其中一個答案，該鏈接將查詢字符串放入servlet的url中，以檢查對實際答案的選擇答案。在一個java bean中servlet的值
我也想說一點我很新，在這我知道我的servlet是錯的我只是不明白該怎麼做：P謝謝大家花時間看看這個！
這裏是JSP：
<html>
<link rel="stylesheet" type="text/css" href="css/Millionaire.css">
<body>
<form method="get">
<img src="img/mlogo.jpg" >
<table>
<th> Question: </th>
<th>${Bean.Question}</th>
</table>
<br>
<table>
<tr>
<td><a href="?selectedAnswer=a">A: ${Bean.question} </a></td>
<td><a href="?selectedAnswer=b">B: ${Bean.a2} </a></td>
</tr>
<tr>
<td><a href="?selectedAnswer=c">C: ${Bean.a3} </a></td>
<td><a href="?selectedAnswer=d">D: ${Bean.a4} </a></td>
</tr>
</table>
<br>
<br>
<table>
<th> Life-Lines </th>
<tr>
<td><a href="?selectedLifeLine=1">Skip</a></td>
<td><a href="?selectedLifeLine=2">Skip</a></td>
<td><a href="?selectedLifeLine=3">Skip</a></td>
</tr>
</table>
<br>
<br>
<div><input type="submit" value="Final Answer"><div>
</form>
</body>
</html>
這裏是我的Servlet：
包分配1;
import java.io.*;
import javax.servlet.*;
import javax.servlet.http.*;
import assignment1.question1;
/**
*
* @author Powa
*/
public class Servlet extends HttpServlet{
@Override
public void doGet(HttpServletRequest request, HttpServletResponse response)
throws IOException, ServletException{
response.setContentType("text/html");
PrintWriter out = response.getWriter();
HttpSession session = request.getSession();
question1.getAttribute("question");
session.setAttribute("Bean","Question");
session.setAttribute("Bean","a1");
session.setAttribute("Bean","a2");
session.setAttribute("Bean","a3");
session.setAttribute("Bean","a4");
}
}
最後這裏是第一個問題豆：
包分配1;
/**
*
* @author Powa
*/
public class question1 implements java.io.Serializable {
private String question = "What type of Pokemon is Pikachu?";
private String a1 = "Fire";
private String a2 = "Water";
private String a3 = "Grass";
private String a4 = "Electric";
private String answer = "Electric";
/**
* @return the question
*/
public String getQuestion() {
return question;
}
/**
* @param question the question to set
*/
public void setQuestion(String question) {
this.question = question;
}
/**
* @return the a1
*/
public String getA1() {
return a1;
}
/**
* @param a1 the a1 to set
*/
public void setA1(String a1) {
this.a1 = a1;
}
/**
* @return the a2
*/
public String getA2() {
return a2;
}
/**
* @param a2 the a2 to set
*/
public void setA2(String a2) {
this.a2 = a2;
}
/**
* @return the a3
*/
public String getA3() {
return a3;
}
/**
* @param a3 the a3 to set
*/
public void setA3(String a3) {
this.a3 = a3;
}
/**
* @return the a4
*/
public String getA4() {
return a4;
}
/**
* @param a4 the a4 to set
*/
public void setA4(String a4) {
this.a4 = a4;
}
/**
* @return the answer
*/
public String getAnswer() {
return answer;
}
/**
* @param answer the answer to set
*/
public void setAnswer(String answer) {
this.answer = answer;
}
}
當我使用session.getAttrbute喜歡你說我得到一個錯誤說「不靜態方法getA1（）不能從靜態上下文中引用 – 2014-10-12 19:06:40