2011-01-26 81 views
1

我正在構建一個界面,其中當用戶點擊一個目標時,他們顯示一個新菜單,該界面有多個此目標實例,每個目標顯示相同的菜單,但是我只想顯示已被點擊的目標下的菜單,此刻,無論目標是什麼,我點擊所有的菜單變得可見。jquery只顯示/隱藏但只有一個實例

$('.statuses').hide(); 
$('.employer .status').click(function(e){ 
    alert('clicked'); 
    $('.employer .status').next('.statuses').show(); 
}); 

而我的HTML

<div id="left-column"> 
<?php foreach($jobs as $j): ?> 
<p><strong><?php echo $j['jobtitle']; ?></strong> &pound;<?php echo $j['salary']; ?>, <?php echo $j['job_summary']?> </p> 
    <ul> 
    <?php foreach($applications as $a): ?> 
     <?php if ($j['jobtitle'] == $a['jobtitle']): ?> 
      <li> 
       <img src="/media/uploads/candidates/<?php echo preg_replace('/(.gif|.jpg|.png)/', '_thumb$1', $a['profile_image']);?>" width="90" height="60" alt="Hello"/> 
       <p><?php echo $a['name']; ?></p> 
       <p class="<?php echo $a['status'];?> status"><?php echo ucfirst($a['status']);?></p> 
       <div class="statuses"> 
        <p class="status pending"><a href="/employer/status/aid/<?php $a['id'];?>/pending">Pending</a></p> 
        <p class="status unsuccessful"><a href="/employer/status/aid/<?php $a['id'];?>/unsuccessful">Unsuccessful</a></p> 
        <p class="status successful"><a href="/employer/status/aid/<?php $a['id'];?>/successful">Successful</a></p> 
       </div> 
       <p class="date"><?php echo date("d.m.Y", $a['created_at']);?></p> 
      </li> 
     <?php endif; ?> 
    <?php endforeach; ?> 
</ul> 
<?php endforeach; ?> 

回答

4
$('.statuses').hide(); 
$('.employer .status').click(function(e){ 
    $(this).next('.statuses').show(); 
});