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我正在創建3個下拉列表，這是基於彼此的選擇，所以第一選擇我正常，但第二個依賴於第一個選擇，第三個依賴於第二個選擇這是表結構是這樣php mysql填充幾個動態下拉列表
類別的子類別和subsubcategory
這是代碼
<?php
require "config.php"; // Database details
?>
<!doctype html public "-//w3c//dtd html 3.2//en">
<html>
<head>
<title>Demo of Three Multiple drop down list box from plus2net</title>
<meta name="GENERATOR" content="Arachnophilia 4.0">
<meta name="FORMATTER" content="Arachnophilia 4.0">
<SCRIPT language=JavaScript>
function reload(form)
{
var val=form.cat.options[form.cat.options.selectedIndex].value;
self.location='dd3.php?cat=' + val ;
}
function reload3(form)
{
var val=form.cat.options[form.cat.options.selectedIndex].value;
var val2=form.subcat.options[form.subcat.options.selectedIndex].value;
self.location='dd3.php?cat=' + val + '&cat3=' + val2 ;
}
</script>
</head>
<body>
<?
$quer2=mysql_query("SELECT DISTINCT category,cat_id FROM category order by category");
$cat=$_GET['cat'];
if(isset($cat) and strlen($cat) > 0){
$quer=mysql_query("SELECT DISTINCT subcategory,subcat_id FROM subcategory where cat_id=$cat order by subcategory");
}else{$quer=mysql_query("SELECT DISTINCT subcategory,subcat_id FROM subcategory order by subcategory"); }
$cat3=$_GET['cat3'];
if(isset($cat3) and strlen($cat3) > 0){
$quer3=mysql_query("SELECT DISTINCT subcat2 FROM subcategory2 where subcat_id=$cat3 order by subcat2");
}else{$quer3=mysql_query("SELECT DISTINCT subcat2 FROM subcategory2 order by subcat2"); }
echo "<form method=post name=f1 action='dd3ck.php'>";
echo "<select name='cat' onchange=\"reload(this.form)\"><option value=''>Select one</option>";
while($noticia2 = mysql_fetch_array($quer2)) {
if($noticia2['cat_id'][email protected]$cat){echo "<option selected value='$noticia2[cat_id]'>$noticia2[category]</option>"."<BR>";}
else{echo "<option value='$noticia2[cat_id]'>$noticia2[category]</option>";}
}
echo "</select>";
echo "<select name='subcat' onchange=\"reload3(this.form)\"><option value=''>Select one</option>";
while($noticia = mysql_fetch_array($quer)) {
if($noticia['subcat_id'][email protected]$cat3){echo "<option selected value='$noticia[subcat_id]'>$noticia[subcategory]</option>"."<BR>";}
else{echo "<option value='$noticia[subcat_id]'>$noticia[subcategory]</option>";}
}
echo "</select>";
echo "<select name='subcat3' ><option value=''>Select one</option>";
while($noticia = mysql_fetch_array($quer3)) {
echo "<option value='$noticia[subcat2]'>$noticia[subcat2]</option>";
}
echo "</select>";
echo "<input type=submit value='Submit the form data'></form>";
?>
</body>
</html>
誰能幫助我？
，這是當我運行這段代碼
0){ $quer=mysql_query("SELECT DISTINCT subcategory,subcat_id FROM subcategory where cat_id=$cat order by subcategory"); }else{$quer=mysql_query("SELECT DISTINCT subcategory,subcat_id FROM subcategory order by subcategory"); } $cat3=$_GET['cat3']; if(isset($cat3) and strlen($cat3) > 0){ $quer3=mysql_query("SELECT DISTINCT subcat2 FROM subcategory2 where subcat_id=$cat3 order by subcat2"); }else{$quer3=mysql_query("SELECT DISTINCT subcat2 FROM subcategory2 order by subcat2"); } echo "
"; echo ""; echo ""; echo ""; echo "
"; ?>
您的PHP代碼出現問題......正確顯示。 – bwoebi 2013-04-21 18:07:21
上面的代碼是我寫的，但第二它不是一個PHP代碼它是瀏覽器上的輸出，當我嘗試運行代碼 – user2288138 2013-04-21 18:09:43
你確定有正確的'<？php'-Tags（例如沒有' <？'，只有'<？php'？），並且你的文件名以'.php'結尾？ – bwoebi 2013-04-21 18:11:52