我得到這個錯誤在日食附近更新查詢中的語法錯誤?在食,但在MySQL工作臺工作
com.mysql.jdbc.exceptions.jdbc4.MySQLSyntaxErrorException:您的SQL語法錯誤;檢查與您的MySQL服務器版本相對應的手冊,以便在''附近使用正確的語法'? ,登錄=? ,pwd =? WHERE登錄名= 'PP'」位於第1行
這是我的查詢在我的源代碼:
String query2 = "UPDATE usuarios SET nombre = ? , login = ? , pwd = ? WHERE login = '" + login2 + "'";
這是從我的方法在整個代碼:
private void modificar() {
// Prints the content of the table
String query = "SELECT * FROM usuarios";
try {
pst = con.Conectar().prepareStatement(query);
rs = pst.executeQuery(query);
// Itarate over the registries
int i = 0;
while (rs.next()) {
i++;
//print them
System.out.println(i + " " + rs.getString("id") + " " + rs.getString("login"));
}
//There are X registries
System.out.println("Existen " + i + " usuarios actualmente");
pst.close();
//Wich registry do you need to modify?
System.out.println("Ingrese el login del usuarios a modificar");
String login2 = scanner.nextLine();
System.out.println("Ingrese datos a modificar");
System.out.print("Nombre: ");
nombre = scanner.nextLine();
System.out.print("Login: ");
login = scanner.nextLine();
System.out.print("Password: ");
pwd = scanner.nextLine();
String query2 = "UPDATE usuarios SET nombre = ? , login = ? , pwd = ? WHERE login = '" + login2 + "'";
pst = con.Conectar().prepareStatement(query2);
pst.setString(1, nombre);
pst.setString(2, login);
pst.setString(3, pwd);
/*
* Aqui da error de sintaxis en query2
*/
pst.executeUpdate(query2);
pst.close();
String query3 = "SELECT * FROM usuarios where login =" + login;
pst = con.Conectar().prepareStatement(query3);
rs = pst.executeQuery(query3);
rs.next();
System.out.println("ahora quedo asi " + rs.getString("login"));
} catch (SQLException e) {
// TODO: handle exception
e.printStackTrace();
} finally {
cerrarConsultas();
}
}
但在MySQL Workbench中使用它時工作正常,這是我在工作臺中的測試。
prepare insertar from "UPDATE usuarios SET nombre = ?, login = ?, pwd = ? WHERE login = 'pp'";
-- "UPDATE usuarios SET nombre = ?, login = ?, pwd = ? WHERE login = 'pablo'";
set @nombre = 'pp';
set @login = 'pp';
set @pwd = 'pp';
execute insertar using @nombre, @login, @pwd;
deallocate prepare insertar;
我已經試過,甚至與字面qoutes,仍然無法正常工作。
String query2 = "UPDATE usuarios SET `nombre` = ? , `login` = ? , `pwd` = ? WHERE login = '" + login2 + "'";
也試過:
String query2 = "UPDATE usuarios SET `nombre` = ? , `login` = ? , `pwd` = ? WHERE login = "+ login2;
相同的結果。
哦親愛的上帝!我要用我的cruzer刀片usb棒自殺!...謝謝! –