問: DBL_MIN是最小正雙倍嗎?DBL_MIN是最小的正數倍嗎?
下面的代碼似乎用no來解釋這個問題。但是,如果這是真的,DBL_MIN如何定義以及它的用途或目的是什麼。
平臺:Windows7的&的Visual Studio 2013
double next_to_zero = std::nextafter(0.0,DBL_MIN);
bool b = DBL_MIN <= next_to_zero;
std::cout << std::boolalpha
<< "is dbl_min the smallest representable double? "
<< b << '\n';
std::cout << std::setprecision(56)
<< "dbl_min = " << DBL_MIN << '\n'
<< "next to zero = " << next_to_zero;
輸出:
是DBL_MIN表示的最小雙?假
DBL_MIN = 2.2250738585072013830902327173324040642192159804623318306e-308
接零= 4.9406564584124654417656879286822137236505980261432476443e-324
C++的std :: numeric_limits ::分鐘文檔:http://en.cppreference.com/w/cpp/types/numeric_limits/min –