嘗試和簡化初學者

Question

有沒有辦法簡化代碼流程，以便busy = 0和print busy不必兩次出現？

busy = 1 
try: 
    print 1/0 
    busy = 0 
    print busy 
except:  
    busy = 0 
    print busy 
    raise 

Answer 1

你可以把它的finally子句中：

try: 
    print 1/0 
except: 
    raise 
finally: 
    busy = 0 
    print busy 

但作爲@Ryan在評論中提到，現在你已經得到的代碼except:子句中無用位。所以，你可以這樣做：

try: 
    print 1/0 
finally: 
    busy = 0 
    print busy 

Answer 2

好吧，你可以把公共代碼的try-catch塊後finally塊，這樣的事情：

busy = 1 
try: 
    print 1/0 
except:  
    raise 
finally : 
    busy = 0 
    print busy 

當你想設置busy = 0和print busy不論try-catch，你可以將內的try-catch以外的通用代碼放在最終執行。

您可以參考this documentation瞭解更多。

Answer 3

使用finally條款或except塊使用的功能。

busy = 1 

def final(busy): 
    print busy 
    return busy 

try: 
    print 1/0 
except: 
    busy = final(0) #sets busy to 0