PHP的strtotime上週每天

Question

您好我有一個從哪裏

`timestamp` >= '".$monS."' AND `timestamp` < '".$sunE."' 

這裏是如何$monS和$sunE定義數據庫中選擇一個查詢：

$startTime = "00:00:00"; 
$endTime = "23:59:59"; 

$today = date('l', strtotime("now")); 

if($today == "Monday"){ 
    $monS = strtotime("yesterday -7 days $startTime"); 
    $sunE = strtotime("yesterday -1 days $endTime"); 
} 
    if($today == "Tuesday"){ 
    $monS = strtotime("yesterday -8 days $startTime"); 
    $sunE = strtotime("yesterday -2 days $endTime"); 
} 
if($today == "Wednesday"){ 
    $monS = strtotime("yesterday -9 days $startTime"); 
    $sunE = strtotime("yesterday -3 days $endTime"); 
} 
if($today == "Thursday"){ 
    $monS = strtotime("yesterday -10 days $startTime"); 
    $sunE = strtotime("yesterday -4 days $endTime"); 
} 
if($today == "Friday"){ 
    $monS = strtotime("yesterday -11 days $startTime"); 
    $sunE = strtotime("yesterday -5 days $endTime"); 
} 
if($today == "Saturday"){ 
    $monS = strtotime("yesterday -12 days $startTime"); 
    $sunE = strtotime("yesterday -6 days $endTime"); 
} 
if($today == "Sunday"){ 
    $monS = strtotime("yesterday -13 days $startTime"); 
    $sunE = strtotime("yesterday -7 days $endTime"); 
} 

它的工作原理然而，大多數情況下，我認爲週末的行數可能不正確。我的網站上的工作人員表示，它並不包括週六和週日。我的腳本看起來好嗎？

Answer 1

它看起來像你想得：

查找在MySQL在一週前的一切過去的這個星期天。

要做到這一點，我會使用當前的星期幾來查找星期日，然後減去一個星期。

$dow = date('N'); // current DOW – 0 = Sunday, 1 = Monday, 2 = Tues... 
$now = time(); 
$sunE = $now - (24 * 3600 * $dow); // 24 * 3600 = one day in seconds 
$monS = $sunE - (24 * 3600 * 7);