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裏面的功能函數和change
函數在那裏。如何傳遞addListener
結果change
函數中使用JavaScript我該如何通過javascript addListener函數值來改變
$(document).ready(function() {
// find pincode
var input = document.getElementById('location_input');
var options = {
types: ['address'],
componentRestrictions: {
country: 'in'
}
};
autocomplete = new google.maps.places.Autocomplete(input, options);
var pincode;
google.maps.event.addListener(autocomplete, 'place_changed', function fun1() {
var place = autocomplete.getPlace();
for (var i = 0; i < place.address_components.length; i++) {
for (var j = 0; j < place.address_components[i].types.length; j++) {
if (place.address_components[i].types[j] === "postal_code") {
pincode = place.address_components[i].long_name;
fun2(pincode);
//alert(pincode);
} //return pincode;
}
}
});
$('input[type="checkbox"],#location_input').change(function fun2(val) {
var ids = ['filter_AFFILIATION_1', 'filter_AFFILIATION_2', 'filter_AFFILIATION_3', 'filter_AFFILIATION_4'];
var data = {};
for (var i = 0; i < ids.length; i++) {
if (document.getElementById(ids[i]).checked === true) {
data['request' + i] = $('#' + ids[i]).val();
}
}
var pincode = val;
alert(pincode);
console.log(pincode);
});
});
這裏fun1
和fun2
兩種功能。我怎麼能通過fun1
pincode
值fun2
裏面?
我嘗試調用pincode值到fun2裏面,但我沒有得到我得到一個對象,但我怎麼能idequalgy pincode對象的值。我想讓ajax同時調用pincode和更改函數值,但我沒有得到兩個值在一起 – somesh
我添加了工作代碼到我的答案。試試吧 –
並閱讀https://api.jquery.com/change/關於使用回調事件。 –