我有一個PHP腳本和MSSQL表,我被存儲在$right_answer
在變量接聽鍵和用戶選擇的在$user_answer_select
答案的格式是這樣的PHP測驗腳本答案亮點
5+10?
A) 10
B) 15
C) 20
D) 25
E) 50
Answer key: B
我想要什麼要做的是在B旁邊放置一個複選標記,如果它是正確的,並且X如果是錯誤的,我將如何在這裏做if else語句?
這是代碼我現在有
if(($user_answer_select == $right_answer) && $user_answer_select == 'a') $a_sel = "<img src=\"tick_icon.gif\">";
else if(($user_answer_select == $right_answer) && $user_answer_select == 'b') $b_sel = "<img src=\"tick_icon.gif\">";
else if(($user_answer_select == $right_answer) && $user_answer_select == 'c') $c_sel = "<img src=\"tick_icon.gif\">";
else if(($user_answer_select == $right_answer) && $user_answer_select == 'd') $d_sel = "<img src=\"tick_icon.gif\">";
else if(($user_answer_select == $right_answer) && $user_answer_select == 'e') $e_sel = "<img src=\"tick_icon.gif\">";
這是錯誤的,因爲一些沒有答案是突出顯示爲真實的問題。有什麼辦法做到這一點?
我說得對不對,你沒有一個具體的問題,只是想用它來編寫解決您的問題的代碼? – vissi 2012-04-11 22:29:39
我將展示我在這裏有什麼 – Grigor 2012-04-11 22:30:37
曾聽說過數組? – 2012-04-11 22:32:15