我有克隆和更改問題。克隆和選擇框onchange輸入文本的更改值
$(document).ready(function() {
addBarang();
});
function addBarang() {
var new_barang = $(".hidden_input").find(".barang_in").clone().addClass("barang_in_clone");
$(".target_clone:last").append(new_barang);
// $(".barang_in_clone:has(select)").addClass("select2");
}
$('body').on('click', '.btn_kurangi_barang', function() {
$(this).closest('.barang_in_clone').remove();
});
function showModel(id){
if(id === ''){
$("input[name=show]").val("");
}else if(id === "1"){
$("input[name=show]").val("foo");
}else if(id === "2"){
$("input[name=show]").val("bar");
}else{
$("input[name=show]").val("too");
}
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<body>
<div class="hidden_input" style="display: none">
<div class="barang_in">
<label class="col-md-4 control-label">Kode Hanca</label>
<select onchange='showModel(this.value)' name="id_vendor_detail" class="form-control" required="">
<option value="">- PILIH -</option>
<option value="1">- Orange -</option>
<option value="2">- Pink -</option>
<option value="3">- Red -</option>
</select>
<button onclick="addBarang()" type="button" data-toggle="tooltip" data-placement="top" title="tambah vendor" class="btn btn-info btn-flat btn-xs pull-left btn_tambah_vendor"><i class="fa fa-plus"></i> add</button>
<button type="button" data-toggle="tooltip" data-placement="top" title="kurangi barang" class="btn btn-danger btn-flat btn-xs pull-right btn_kurangi_barang"><i class="fa fa-minus"></i> Remove</button>
<input type='text' name='show'>
</div>
</div>
<div class='target_clone'>
</div>
</body>
當我克隆的數據,其顯示出許多選擇框。當我選擇選擇框時,我想要根據if else
的值更改<input type='text' name='show'>
。我能怎麼做 ?
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請運行該片段 –
與虛擬文字是什麼? – madalinivascu
輸入值在更改selectbox選項時確實發生了變化,最新的問題實際上是 –