您可以使用multiprocessing.Process和Condition來做到這一點。請試試這個代碼:
import multiprocessing
import time
class Task(multiprocessing.Process):
counter = 0
name = None
event = None
another_tasks = set()
def __init__(self, mgr_dict, cond):
super(Task, self).__init__()
self.mgr_dict = mgr_dict
self.cond = cond
cls = self.__class__
cls.counter += 1
self.name = '{} {}'.format(cls.__name__, cls.counter)
self.mgr_dict[self.name] = 0
def value(self):
return self.mgr_dict[self.name]
def run(self):
while True:
with self.cond:
self.cond.wait()
self.mgr_dict[self.name] += 1
class SubTask(Task):
pass
class MainTask(Task):
subtasks = set()
def working(self):
with self.cond:
self.cond.notify_all()
def start(self):
super(MainTask, self).start()
for subtask in self.subtasks:
subtask.start()
def create_subtask(self):
subtask = SubTask(self.mgr_dict, condition)
self.subtasks.add(subtask)
def join(self):
self.mgr_dict[self.name]
def shutdown(self):
self.exit.set()
event = multiprocessing.Event()
if __name__ == '__main__':
mgr = multiprocessing.Manager()
mgr_dict = mgr.dict()
condition = multiprocessing.Condition()
task1 = MainTask(mgr_dict, condition)
subtask1 = task1.create_subtask()
subtask2 = task1.create_subtask()
subtask3 = task1.create_subtask()
subtask4 = task1.create_subtask()
subtask5 = task1.create_subtask()
task1.start()
while task1.value() < 100:
time.sleep(1)
task1.working()
print mgr_dict
結果:
{'MainTask 1': 0, 'SubTask 1': 0, 'SubTask 2': 0, 'SubTask 3': 0, 'SubTask 4': 0, 'SubTask 5': 0}
{'MainTask 1': 1, 'SubTask 1': 1, 'SubTask 2': 1, 'SubTask 3': 1, 'SubTask 4': 1, 'SubTask 5': 1}
.
.
.
{'MainTask 1': 100, 'SubTask 1': 100, 'SubTask 2': 100, 'SubTask 3': 100, 'SubTask 4': 100, 'SubTask 5': 100}
感謝您的答覆,但我想知道什麼我是否可以從另一個單獨的「蟒蛇過程」查詢task.progress_percent,有點兒進程之間的「IPC」 –
Ops ..對不起=) 您可以使用共享名稱空間來執行此操作。如果你願意,我可以舉個例子。 – arkadyzalko
讚賞如果你能展示一個例子,更多的可以'共享命名空間'爲不同的python進程工作而不是由進度A產生? –