php上的javascript問題

Bellow是我的php代碼。php上的javascript問題

<div class="poller"> 

       <div class="poller_question" id="poller_question2"> 
       <p class="pollerTitle">Would you join a Community Action Committee?</p> 
<p class="pollerOption"><input type="radio" value="6" name="vote[2]" id="pollerOption6"> 
<label for="pollerOption6" id="optionLabel6">Yes</label></p><p class="pollerOption"> 
<input type="radio" value="7" name="vote[2]" id="pollerOption7"><label for="pollerOption7" 
id="optionLabel7">Maybe</label></p><p class="pollerOption"><input type="radio" value="8" 
name="vote[2]" id="pollerOption8"><label for="pollerOption8" id="optionLabel8">No</label></p>   
       <a href="#" onclick="castMyVote(2,document.forms[0])"><imgsrc="images/vote_button.gif" border="0"></a> 

       </div> 
       <div class="poller_waitMessage" id="poller_waitMessage2"> 
        Getting poll results. Please wait... 
       </div> 
       <div class="poller_results" id="poller_results2"> 
       <!-- This div will be filled from Ajax, so leave it empty --></div> 
      </div>

貝婁是我的javascript代碼

function castMyVote(pollId,formObj) 
{ 
    var elements = formObj.elements['vote[' + pollId + ']']; 
    var optionId = false; 
    for(var no=0;no<elements.length;no++){ 
     if(elements[no].checked)optionId = elements[no].value; 
    } 
    Poller_Set_Cookie('dhtmlgoodies_poller_' + pollId,'1',6000000); 
    if(optionId){ 

     var ajaxIndex = ajaxObjects.length; 
     ajaxObjects[ajaxIndex] = new sack(); 
     ajaxObjects[ajaxIndex].requestFile = serverSideFile + '?pollId=' + pollId + '&optionId=' + optionId; 
     prepareForPollResults(pollId); 
     ajaxObjects[ajaxIndex].onCompletion = function(){ showVoteResults(pollId,ajaxIndex); }; // Specify function that will be executed after file has been found 
     ajaxObjects[ajaxIndex].runAJAX();  // Execute AJAX function  

    } 
}

形式的PHP我調用一個名爲「castMyVote」 .The JavaScript方法JavaScript是

var elements = formObj.elements['vote[' + pollId + ']'];

創建問題？爲什麼？如何解決呢？VAR元素沒有價值

來源

2010-01-06 HelloBD

你能解釋一下你的問題到底在哪？ – junmats 2010-01-06 05:46:38

你應該投資一些格式。除此之外，它使調試更容易。 – 2010-01-06 09:29:32

你得到的錯誤是什麼？ – 2010-01-06 05:36:48

嘗試

var elements = document.getElementsByName("vote["+pollId+"]");

來源

2010-01-06 05:46:53 YOU

如果你的問題是，你的元素變量沒有得到正確的值，那是因爲你的函數的第二個參數CastMyVote需要一個表單，但是您的html中沒有表單。試試這個：

<div class="poller"> 
<form method="post" action="#"> 
       <div class="poller_question" id="poller_question2"> 
       <p class="pollerTitle">Would you join a Community Action Committee?</p> 
<p class="pollerOption"><input type="radio" value="6" name="vote[2]" id="pollerOption6"> 
<label for="pollerOption6" id="optionLabel6">Yes</label></p><p class="pollerOption"> 
<input type="radio" value="7" name="vote[2]" id="pollerOption7"><label for="pollerOption7" 
id="optionLabel7">Maybe</label></p><p class="pollerOption"><input type="radio" value="8" 
name="vote[2]" id="pollerOption8"><label for="pollerOption8" id="optionLabel8">No</label></p>   
       <a href="#" onclick="castMyVote(2,document.forms[0])"><imgsrc="images/vote_button.gif" border="0"></a> 

       </div> 
       <div class="poller_waitMessage" id="poller_waitMessage2"> 
        Getting poll results. Please wait... 
       </div> 
       <div class="poller_results" id="poller_results2"> 
       <!-- This div will be filled from Ajax, so leave it empty --></div> 
</form> 
      </div>

我只是把你的div和輸入的表單內。

編輯：您的<imgsrc="images/vote_button.gif" border="0">。錯字錯誤？

來源

2010-01-06 06:09:36 junmats

php上的javascript問題

回答

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