獲得一個錯誤：列表分配索引超出範圍

Question

我正在一個錯誤列表分配索引超出範圍下面的代碼：

n=input("How many numbers?\n") 
print "Enter ",n," numbers..." 
a=[] 
for i in range(0,n): 
    a[i]=input() 

elem=input("Enter the element to be searched: ") 

for i in range(0,n): 
    if a[i]==elem: 
     flag=1 
     break 

if flag==1: 
    print "Item is present in the list" 
else: 
    print "Item is not present in the list" 

Answer 1

添加某種類型的安全性INT，採用列表法追加和運營商在：

n = input("How many numbers?\n") 
n = int(n) 
print "Enter ", n, " numbers..." 
a = [] 
for i in range(n): 
    x = input() 
    a.append(x) 

elem = input("Enter the element to be searched: ") 

if elem in a: 
    print "Item is present in the list" 
else: 
    print "Item is not present in the list" 

Answer 2

你設置列表索引沒有它宣稱。見：

a=[] 

然後，你想要訪問一些索引？你正在閱讀一個字符串與輸入，在使用前轉換它。事情會是這樣的：

n = int(n) 
a= []*n 

Answer 3

使用它像這樣，

n=input("How many numbers?\n") 
print "Enter ",n," numbers..." 
# assigning with n times zero values which will get overwritten when you input values. 
a=[0]*n 
for i in range(0,n): 
    a[i]=input() 

elem=input("Enter the element to be searched: ") 

for i in range(0,n): 
    if a[i]==elem: 
     flag=1 
     break 

if flag==1: 
    print "Item is present in the list" 
else: 
    print "Item is not present in the list"