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我試圖在點擊修改鏈接時替換某些表格元素，實際上它會替換掉 ，但是href屬性不正確。 有什麼不對嗎？請幫忙，謝謝！jquery replaceWith問題
HTML：
<html>
<head>
<script src="http://code.jquery.com/jquery-latest.js"></script>
</head>
<body>
<table id="department_list_table" border=1>
<tbody>
<tr id = 1>
<td>department A</td>
<td align="center"><a href = "#" onclick = "department_action('modify', 1, 'department A')">modify</a></td>
<td align="center"><a href = "#" onclick = "department_action('delete', 1, 'department A')">delete</a></td>
</tr>
<tr id = 2>
<td>department B</td>
<td align="center"><a href = "#" onclick = "department_action('modify', 2, 'department B')">modify</a></td>
<td align="center"><a href = "#" onclick = "department_action('delete', 2, 'department B')">delete</a></td>
</tr>
</tbody>
</table>
</body>
的jQuery：
var id = 3;
var name = 'department C';
$("#department_list_table tbody tr#1").replaceWith(
'<tr id =' + id + '>' +
'<td>' + name + '</td>' +
'<td align="center"><a href="#" onclick="department_action("modify",'+ id +',' + name + ')">modify</a></td>' +
'<td align="center"><a href="#" onclick="department_action("delete",'+ id +',' + name + ')">delete</a></td>' +
'</tr>');
結果的螢火：
<tr id="3">
<td>department C</td>
<td align="center">
**<a c)"="" modify",3,department="" onclick="department_action(" href="#">modify</a>**
</td>
<td align="center">
**<a c)"="" delete",3,department="" onclick="department_action(" href="#">delete</a>**
</td>
</tr>
非常感謝AlienWebguy！ – user658619
很高興幫助！ :) – AlienWebguy