我希望我能解釋我想要做的 - 真的希望有人能夠幫助！這裏是數組我與PHP：需要根據維中的一個鍵合併/排序多維數組

(
    [0] => Array 
     (
      [city] => Middletown 
      [state] => OH 
      [freq] => 146.610 
      [pl] => 77.0 
      [call] => W8BLV 
      [distance] => 0.0 
      [notes] => ottel 
     ) 

    [1] => Array 
     (
      [city] => Middletown 
      [state] => OH 
      [freq] => 146.715 
      [pl] => 
      [call] => N8COZ 
      [distance] => 0.0 
      [notes] => ct 
     ) 

    [2] => Array 
     (
      [city] => Middletown 
      [state] => OH 
      [freq] => 147.315 
      [pl] => 77.0 
      [call] => W8JEU 
      [distance] => 0.0 
      [notes] => ottel 
     ) 

    [3] => Array 
     (
      [city] => Middletown 
      [state] => OH 
      [freq] => 443.5370 
      [pl] => 118.8 
      [call] => W8MUM 
      [distance] => 0.0 
      [notes] => oe oe 
     ) 

    [4] => Array 
     (
      [city] => Middletown 
      [state] => OH 
      [freq] => 444.4750 
      [pl] => 100.0 
      [call] => AG8Y 
      [distance] => 0.0 
      [notes] => ottel 
     ) 

    [5] => Array 
     (
      [city] => Middletown 
      [state] => OH 
      [freq] => 444.8250 
      [pl] => 77.0 
      [call] => W8BLV 
      [distance] => 0.0 
      [notes] => oel 
     ) 

    [6] => Array 
     (
      [city] => Monroe 
      [state] => OH 
      [freq] => 443.0870 
      [pl] => 
      [call] => KC8ECK 
      [distance] => 4.3 
      [notes] => oep 
     ) 

    [7] => Array 
     (
      [city] => Franklin 
      [state] => OH 
      [freq] => 145.290 
      [pl] => 118.8 
      [call] => WB8ZVL 
      [distance] => 5.5 
      [notes] => o(ca)r 
     ) 

    [8] => Array 
     (
      [city] => Franklin 
      [state] => OH 
      [freq] => 442.4250 
      [pl] => 77.0 
      [call] => WE8N 
      [distance] => 5.5 
      [notes] => Oae(ca) 
     ) 

    [9] => Array 
     (
      [city] => Franklin 
      [state] => OH 
      [freq] => 443.1500 
      [pl] => 118.8 
      [call] => WB8ZVL 
      [distance] => 5.5 
      [notes] => o(ca)r 
     ) 

    [10] => Array 
     (
      [city] => Springboro 
      [state] => OH 
      [freq] => 145.490 
      [pl] => 77.0 
      [call] => W8CYE 
      [distance] => 8.9 
      [notes] => oe 
     ) 

)

輸出工作，我希望得到的需求是這樣的：

$rpt[0] ="Middletown 146.61/77, 146.715, 147.315/77, 443.537/118.8, 444.475/100, 444.825/77"; 
$rpt[1] = "Monroe 443.087"; 
$rpt[2] = "Franklin 145.29/118.8, 442.425/77, 443.15/118.8"; 
$rpt[3] = "Springboro 145.49/77"

我最感興趣的是城市，頻率的領域， PL - 如果你看看第一個數組，我已經刪除了輸出數組上的尾隨零。也有幾次，當我可能需要使用呼叫字段和筆記字段時，但是如果有人能指向我正確的方向，我可能會計算出我需要的其餘部分 - 呼叫字段和筆記字段不會經常使用。我已經嘗試了幾個不同的foreach循環，但我仍然是PHP的新手 - 而且我所做的工作並不正確，而且我在這點上需要一些幫助。

在此先感謝您的幫助，樂華，KD8BXP

來源

2010-07-21 LeRoy Miller

foreach($input_array as $item) { 
    $output_array[$item['city']][] = array(
      'freq' => $item['freq'], 
      'pl' => $item['pl'] 
     ); 
}

有了這個，$output_array最終將成爲一個關聯數組，它的鍵是城市，其值頻率+ PL數組列表：

Array 
(
    ["Middletown"] => Array 
     (
      [0] => Array 
       (
        [freq] => 146.610, 
        [pl] => 77.0 
       ), 
      [1] => Array 
       (
        [freq] => 146.715, 
        [pl] => 
       ) 
      // etc... 
     ) 
    // etc... 
)

（而且歡迎您 - 琥珀，KC9HTI）

編輯

一旦你運行上面的代碼，你可以使用此代碼來獲得你想要的最終格式：那麼

foreach($output_array as $city => $freq_list) { 
    $freqs = array(); 
    foreach($freq_list as $freq) { 
     $freq_str = $freq['freq']; 
     if($freq['pl']) $freq_str .= "/" . $freq['pl']; 
     $freqs[] = $freq_str; 
    } 
    $rpt[] = $city . " " . implode(", ", $freqs); 
}

$rpt應該有你想要的陣列。

來源

2010-07-21 04:06:22 Amber

琥珀，感謝您的快速答案...不太我所期待的事，但要更接近當時我讓我的自己的！我想我可以爲你工作。非常感謝你的幫助。 LeRoy，KD8BXP – 2010-07-21 04:14:29

嗯。讓我看看我是否可以調整它以更貼近地滿足您的需求。 :) – Amber 2010-07-21 04:20:13

看看我添加在底部的位是否有幫助。 – Amber 2010-07-21 04:25:30

這裏是你需要的東西：

// Here $items is your input array. 

/* First, sort input array by freq */ 

function compareByFreq($a, $b) 
{ 
    if ($a['freq'] == $b['freq']) { 
     return 0; 
    } 
    return ($a['freq'] < $b['freq']) ? -1 : 1; 
} 

uasort($items, 'compareByFreq'); 



/* Aggregate required data */ 

$result = array(); 
foreach($items as $item) 
{ 
    if (isset($result[$item['city']])) { 
     $result[$item['city']] .= ', '. $item['freq']; 
    } else { 
     $result[$item['city']] = $item['city'] . ' ' . $item['freq']; 
    } 
    if (! empty($item['pl'])) { 
     $result[$item['city']] .= '/' . $item['pl']; 
    } 
} 

$result = array_values($result); // get rid of assoc keys

來源

2010-07-21 04:38:07 Serg

PHP：需要根據維中的一個鍵合併/排序多維數組

回答

編輯

相關問題