SOAPtoPOJOTransformer in mule esb

Question

在我的應用程序中，客戶端向Mule ESB發送SOAP請求，所以我想在我的ESB中使用SOAPtoPOJOTransformer，這樣就可以爲我的組件類提供POJO對象。

請給我一個這個變壓器的樣本或代碼片段。

感謝， 納拉亞南

Answer 1

CXF + JAXB會照顧的，對於你。

請參見：http://www.mulesoft.org/documentation/display/MULE3USER/Building+Web+Services+with+CXF

Answer 2

在我的應用程序，我有一個XML聲明我需要使用，這樣我剛纔提到他們對我的流量的所有變壓器。見下文。 （你不需要使用ISO-8859-1）

<?xml version="1.0" encoding="UTF-8"?> 
<mule 
xmlns="http://www.mulesoft.org/schema/mule/core" 
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" 
xmlns:mxml="http://www.mulesoft.org/schema/mule/xml" 
xmlns:vm="http://www.mulesoft.org/schema/mule/vm" 
xmlns:spring="http://www.springframework.org/schema/beans" 
xsi:schemaLocation=" 
    http://www.mulesoft.org/schema/mule/core http://www.mulesoft.org/schema/mule/core/3.2/mule.xsd 
    http://www.mulesoft.org/schema/mule/xml http://www.mulesoft.org/schema/mule/xml/3.2/mule-xml.xsd 
    http://www.mulesoft.org/schema/mule/vm http://www.mulesoft.org/schema/mule/vm/3.1/mule-vm.xsd 
    http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-3.0.xsd"> 

<mxml:jaxb-context 
    name="jaxb-context" 
    packageNames="my.package.v1:my.package.v2:soap.package" /> 

<mxml:jaxb-xml-to-object-transformer 
    name="xml-to-object" 
    encoding="ISO-8859-1" 
    jaxbContext-ref="jaxb-context" 
    ignoreBadInput="true" /> 

<mxml:jaxb-object-to-xml-transformer 
    name="object-to-xml" 
    encoding="ISO-8859-1" 
    jaxbContext-ref="jaxb-context" 
    returnClass="java.lang.String" 
    ignoreBadInput="true" /> 

<byte-array-to-string-transformer 
    name="byte-array-to-string" 
    encoding="ISO-8859-1" 
    returnClass="java.lang.String" /> 

<string-to-byte-array-transformer 
    name="string-to-byte-array" 
    encoding="ISO-8859-1" 
    returnClass="byte[]" /> 

<custom-transformer 
    name="xml-to-xml-stream-reader" 
    class="org.mule.module.xml.transformer.XmlToXMLStreamReader" /> 

<object-to-string-transformer name="object-to-string" /> 

<flow name="ByteArrayToObjectXml"> 

    <vm:inbound-endpoint 
     path="myapp/conversor/byte-array-to-object-xml" 
     exchange-pattern="request-response" /> 

    <transformer ref="byte-array-to-string" /> 
    <transformer ref="xml-to-object" /> 
</flow> 

Answer 3

是的，你需要寫數據編織改造將XML轉換成Java。我正在提供一個示例流程，您需要編寫類似的轉換代碼。

<flow name="getDeltaFlightsFlow"> 
     <http:listener config-ref="HTTP_Listener_Configuration" path="/delta" allowedMethods="GET" doc:name="HTTP"/> 

     <dw:transform-message doc:name="Transform Message"> 
      <dw:set-payload><![CDATA[%dw 1.0 
%output application/xml 
%namespace ns0 http://soap.training.mulesoft.com/ 
--- 
{ 
    ns0#findFlight: { 
     destination: flowVars.code as :string 
    } 
}]]></dw:set-payload> 
     </dw:transform-message> 
     <ws:consumer config-ref="Delta_Service_Consumer" operation="findFlight" doc:name="Delta SOAP Reqst"/> 
     <dw:transform-message metadata:id="fdbaa716-f263-4812-a153-6509b7407ee8" doc:name="Transform Message"> 
      <dw:set-payload><![CDATA[%dw 1.0 
%output application/java 
%namespace ns0 http://soap.training.mulesoft.com/ 
--- 
{ 
    flights: payload.ns0#findFlightResponse.*return map ((return , indexOfReturn) -> { 
     airlineName: return.airlineName, 
     price: return.price, 
     departureDate: return.departureDate, 
     planeType: return.planeType, 
     origin: return.origin, 
     code: return.code, 
     emptySeats: return.emptySeats, 
     destination: return.destination 
    }) 
}]]></dw:set-payload> 
     </dw:transform-message> 
     <logger level="INFO" doc:name="Logger"/> 

    </flow>