我是一個初學者,所以很抱歉,如果這是顯而易見的。Python 3:ValueError:無效文字爲int()與基數10:'0001.0110010110010102e + 22'
我在這裏不知所措。我一直在試圖製作一個加密/解密程序,但我一直收到這個錯誤。我知道在這個問題上還有其他問題,但我仍然無法解決它。
加密器:
import binascii
def text_to_bits(text, encoding='utf-8', errors='surrogatepass'):
bits = bin(int(binascii.hexlify(text.encode(encoding, errors)), 16))[2:]
return bits.zfill(8 * ((len(bits) + 7) // 8))
def text_from_bits(bits, encoding='utf-8', errors='surrogatepass'):
n = int(bits, 2)
return int2bytes(n).decode(encoding, errors)
def int2bytes(i):
hex_string = '%x' % i
n = len(hex_string)
return binascii.unhexlify(hex_string.zfill(n + (n & 1)))
#ENCRYPTION ALGORITHM
algorithm = 61913299
#ASCII ----> NUMBERS
raw = input("Enter text to encrypt:")
binary = text_to_bits(raw)
binary = int(binary)
algorithm = int(algorithm)
encrypted = binary * algorithm
encrypted = str(encrypted)
print(encrypted)
print("Done")
解密:
import sys
import time
def to_bin(string):
res = ''
for char in string:
tmp = bin(ord(char))[2:]
tmp = '%08d' %int(tmp)
res += tmp
return res
def to_str(string):
res = ''
for idx in range(len(string)/8):
tmp = chr(int(string[idx*8:(idx+1)*8], 2))
res += tmp
return res
incorrectpasswords = 0
password=("password")
originpassword = password
x = 1
algorithm = 61913299
while x==1:
passwordattempt =input("Enter Password:")
if passwordattempt == password:
print("Correct")
x = 2
if passwordattempt!= password:
print("Incorrect")
incorrectpasswords = incorrectpasswords + 1
if incorrectpasswords > 2:
if x == 1:
print("Too many wrong attempts, please try again in one minute.")
time.sleep(60)
encrypted = input("Enter numbers to unencrypt:")
encrypted = int(encrypted)
one = encrypted/algorithm
size = sys.getsizeof(one)
one = str(one).zfill(size + 1)
one = int(one)
unencrypted = to_str(one)
x = unencrypted
對於二進制和文本,文本和二進制之間的轉換,我使用了一些代碼,我在網上找到。
不它說哪一行是錯誤? –
@MatthewCiaramitaro是的,對不起。第49行。'one = int(one)' –
與Python早期版本不同,Python 3中的'/'或「真除法」操作符即使在用'ints'調用時也會返回一個浮點數。如果它適合你的算法,你可以使用'//'或者「floor division」,只要它的輸入是'int'就可以返回。 –