如何接受3個參數爲INT

Question

例如：

console> please enter 3 digits: 1 2 3 

我只知道如何使用scanf接受1位：

scanf("%d", &space); 

Answer 1

您可以在多個號碼與scanf函數

閱讀

int a, b, c; 
scanf("%d %d %d", &a, &b, &c); 

Answer 2

你試過：

scanf("%d %d %d", &num1, &num2, &num3); 

那將工作得很好，如果你知道你只想要三個。如果你想要一個可變數目，你需要做一個循環，是這樣的：

#include <stdio.h> 

int main (void) { 
    int i, ch, rc, val, count; 

    // Loop until we get a valid number. 

    rc = 0; 
    while (rc != 1) { 
     printf ("Enter count: "); fflush (stdout); 
     rc = scanf(" %d", &count); 

     // Suck up all characters to line end if bad conversion. 

     if (rc != 1) while ((ch = getchar()) != '\n'); 
    } 

    // Do once for each number. 

    for (i = 1; i <= count; i++) { 
     rc = 0; 
     while (rc != 1) { 
      printf ("\nEnter #% 2d: ", i); fflush (stdout); 
      rc = scanf(" %d", &val); 
      if (rc != 1) while ((ch = getchar()) != '\n'); 
     } 
     printf ("You entered %d\n", val); 
    } 

    return 0; 
} 

運行這給你：

Enter count: 5 

Enter # 1: 10 
You entered 10 

Enter # 2: 20 
You entered 20 

Enter # 3: 30 
You entered 30 

Enter # 4: 40 
You entered 40 

Enter # 5: 99 
You entered 99