您可以使用filter
:
var records = [{"Name":"Bob", "EmployeeID":1234, "StartDate":"12/01/2011"},
{"Name":"Jim", "EmployeeID":4432, "StartDate":"01/12/1997"},
{"Name":"Heather", "EmployeeID":6643, "StartDate":"07/09/2010"}];
var result = records.filter(function(r) { return r["EmployeeID"] == 4432 })[0]||'No record found';
搜索功能,可以實現如下:
function findByEmployeeId(records, employeeId) {
return records.filter(function(r) { return r["EmployeeID"] == employeeId })[0]||null;
}
在一般情況下,如果你有對數據的任何控制,我會建議改變結構讓你的生活更輕鬆。如果您使用下面的結構,你可以直接使用records[employeeId]
訪問記錄:
{ "1234" : {"Name":"Bob", "EmployeeID":1234, "StartDate":"12/01/2011"},
"4432" : {"Name":"Jim", "EmployeeID":4432, "StartDate":"01/12/1997"},
"6643" : {"Name":"Heather", "EmployeeID":6643, "StartDate":"07/09/2010"} }
或者,如果你能使用的ECMAScript 6 https://developer.mozilla.org/en-找到() US/docs/Web/JavaScript/Reference/Global_Objects/Array/find – 2014-11-24 21:08:42
當我嘗試你的函數示例時,控制檯說「records.filter不是一個函數...」 – Adam 2014-11-24 21:16:07
不是每個瀏覽器都有這個,但是我想建議查看[Underscore.js](http://underscorejs.org/),它提供了許多搜索功能。 – stakolee 2014-11-24 21:18:07